Chapter 0: Problem 79
Describe two different ways to factor \(2 x^{2}-7 x-15\).
Short Answer
Expert verified
Two ways to factor \(2x^2-7x-15\) are \((2x+3)(x-5)\) or \((2x-15)(x-1)\).
Step by step solution
01
Trinomial Structure
Observe that the given trinomial is of the form \(ax^2+bx+c\), with \(a=2\), \(b=-7\), and \(c=-15\). Identify the terms and their respective coefficients in the quadratic.
02
Identify Pairs
Identify pairs of numbers that multiply to give a product of \(ac\) (which is \(2*(-15)=-30\)) and sum to \(b\) (which is -7). After some guesses and checks, these pairs are found to be: (-10 and 3) or (-15 and 2).
03
Decompose and Factor
Decompose the middle term into the identified pairs: \(2x^2-10x+3x-15\) or \(2x^2-15x+2x-15\), and factor by grouping.
04
Quadratic Expressions
For the pairs\((-10, 3)\), it factors to \(2x(x-5)+3(x-5)=(2x+3)(x-5)\), and for the pairs (-15, 2), it factors to \((2x^2-15x)+(2x-15)=x(2x-15)-1(2x-15)=(2x-15)(x-1)\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Expressions
Quadratic expressions are polynomial expressions of degree two. They have the standard form of \(ax^2 + bx + c\), where \(a\), \(b\), and \(c\) are constants. The graph of a quadratic expression is a parabola, which can either open upwards or downwards, depending on the sign of \(a\). In our exercise, we are given the quadratic expression: \(2x^2 - 7x - 15\). Here, \(a = 2\), \(b = -7\), and \(c = -15\).
Understanding the coefficients is crucial as they dictate the shape and position of the parabola, as well as the solutions of the quadratic equation.
Understanding the coefficients is crucial as they dictate the shape and position of the parabola, as well as the solutions of the quadratic equation.
- The coefficient \(a\) influences the width and the direction of the parabola.
- The coefficient \(b\) affects the axis of symmetry and the turn direction.
- Finally, \(c\) represents the y-intercept when \(x = 0\).
Factor by Grouping
Factor by grouping is a method used to factorize quadratic expressions, particularly when dealing with trinomials. This technique involves rearranging the terms in a polynomial and grouping them in pairs that can be easily factored separately.
For our quadratic \(2x^2 - 7x - 15\), we start by finding pairs of numbers that multiply to the product of \(a\) and \(c\) (in this case, \(-30\)) and add to \(b\) (which is \(-7\)). After trying different combinations, we find that the pairs \((-10, 3)\) and \((-15, 2)\) satisfy these conditions.
We then break down the middle term, \(-7x\), into these pairs:
For our quadratic \(2x^2 - 7x - 15\), we start by finding pairs of numbers that multiply to the product of \(a\) and \(c\) (in this case, \(-30\)) and add to \(b\) (which is \(-7\)). After trying different combinations, we find that the pairs \((-10, 3)\) and \((-15, 2)\) satisfy these conditions.
We then break down the middle term, \(-7x\), into these pairs:
- \(2x^2-10x+3x-15\)
- \(2x^2-15x+2x-15\)
- \((2x^2-10x) + (3x-15)\)
- \((2x^2-15x) + (2x-15)\)
Trinomial Structure
Trinomial structure is a specific format within quadratic expressions and is vital for understanding how to factor them efficiently. A trinomial expression has three terms, and often, it appears in the standard form \(ax^2 + bx + c\). The factorization process involves transforming this structure into a product of two binomials.
The trinomial \(2x^2 - 7x - 15\) can be transformed by identifying a pair of numbers that fit the criteria of both multiplication and addition.
The trinomial \(2x^2 - 7x - 15\) can be transformed by identifying a pair of numbers that fit the criteria of both multiplication and addition.
- Multiply \(a\) and \(c\) to find pairs that add up to \(b\).
- Use those pairs to break down and rearrange the terms, making perfect binomial factors easier to spot.