Chapter 6: Problem 86
True or False? Justify your answer with a proof or a counterexample. The rectangular coordinates of the point \(\left(4, \frac{5 \pi}{6}\right)\) are \((2 \sqrt{3},-2)\).
Short Answer
Expert verified
False. The correct rectangular coordinates are
(-2\sqrt{3}, 2).
Step by step solution
01
Understand the Problem
The point given is in polar coordinates: \( (r, \theta) = (4, \frac{5 \pi}{6}) \). We need to convert these polar coordinates into rectangular coordinates (Cartesian coordinates) to verify if they equal \((2 \sqrt{3}, -2)\).
02
Convert Polar to Rectangular Coordinates
The conversion from polar coordinates \((r, \theta)\) to rectangular coordinates \((x, y)\) involves two formulas:1. \( x = r \cdot \cos(\theta) \)2. \( y = r \cdot \sin(\theta) \).Given \( r = 4 \) and \( \theta = \frac{5\pi}{6}\), we will use these formulas to find \( x \) and \( y \).
03
Calculate the x-Coordinate
Using the formula \( x = r \cdot \cos(\theta) \), substitute \( r = 4 \) and \( \theta = \frac{5\pi}{6} \):\[ x = 4 \cdot \cos\left(\frac{5\pi}{6}\right) \].Since \( \cos\left(\frac{5\pi}{6}\right) = -\frac{\sqrt{3}}{2} \), the calculation becomes:\[ x = 4 \cdot \left(-\frac{\sqrt{3}}{2}\right) = -2\sqrt{3} \].
04
Calculate the y-Coordinate
Using the formula \( y = r \cdot \sin(\theta) \), substitute \( r = 4 \) and \( \theta = \frac{5\pi}{6} \):\[ y = 4 \cdot \sin\left(\frac{5\pi}{6}\right) \].Since \( \sin\left(\frac{5\pi}{6}\right) = \frac{1}{2} \), the calculation becomes:\[ y = 4 \cdot \frac{1}{2} = 2 \].
05
Compare Calculated Coordinates with Given Coordinates
Compare the calculated rectangular coordinates \((-2\sqrt{3}, 2)\) with the given coordinates \((2\sqrt{3}, -2)\). They do not match, indicating the statement is false.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Polar Coordinates
Polar coordinates are a way of representing points in a plane using a distance from a fixed point and an angle from a fixed direction. The fixed point is known as the pole, and the fixed direction is typically the positive x-axis in standard polar coordinates. This system uses pairs in the form
- \((r, \theta)\),
- where \(r\) is the radius - the line from the pole - and \(\theta\) is the angle measured in radians.
- A negative angle \(\theta\) often means rotating clockwise.
- A negative \(r\) suggests moving in the opposite direction of the angle.
Rectangular Coordinates
Rectangular coordinates, also known as Cartesian coordinates, describe a point's location using two values: one for the horizontal axis (usually called \(x\)) and one for the vertical axis (usually called \(y\)). This system is straightforward and widely used due to its simplicity. To understand this system, think of the plane as divided by an x-axis (horizontal) and a y-axis (vertical). Any point is represented by an ordered pair \((x, y)\), where:
- \(x\) reflects the horizontal distance from the origin.
- \(y\) denotes the vertical distance from the origin.
Coordinate Transformation
Coordinate transformation refers to the process of converting one set of coordinates to another. In the context of polar and rectangular coordinates, this involves mapping points from a circular system to a grid-like system and vice versa. The conversion formulas are rooted in basic trigonometric relationships.
- Polar to Rectangular:
To convert polar coordinates \((r, \theta)\) to rectangular coordinates \((x, y)\), use the formulas:- \(x = r \cdot \cos(\theta)\)
- \(y = r \cdot \sin(\theta)\)
Trigonometric Functions
Trigonometric functions are mathematical functions that relate angles and ratios of triangle sides. They form the backbone of converting polar coordinates to rectangular coordinates.
- Key Functions:
- Sine (\(\sin\)) provides the ratio of the length of the opposite side to the hypotenuse in a right triangle.
- Cosine (\(\cos\)) gives the ratio of the adjacent side's length to the hypotenuse.
- The \(\cos\) function helps determine the x-coordinate.
- The \(\sin\) function finds the y-coordinate.