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[T] Find the first 1000 digits of \(\pi\) using either a computer program or Internet resource. Create a bit sequence \(b_{n}\) by letting \(b_{n}=1\) if the \(n\) th digit of \(\pi\) is odd and \(b_{n}=0\) if the \(n\) th digit of \(\pi\) is even. Compute the average value of \(b_{n}\) and the average value of \(d_{n}=\left|b_{n+1}-b_{n}\right|, n=1, \ldots, 999 .\) Does the sequence \(b_{n}\) appear random? Do the differences between successive elements of \(b_{n}\) appear random?

Short Answer

Expert verified
The average values can provide insights into the randomness of the sequences. If both averages are around 0.5, the sequences appear random.

Step by step solution

01

Obtain the First 1000 Digits of Pi

Use an online resource or a program to generate the first 1000 decimal digits of \(\pi\). For example, the first few digits of \(\pi\) are 3.1415926535... and continue until you reach 1000 digits.
02

Create the Bit Sequence b_n

For each digit in the sequence of \(\pi\), assign a value of 1 to \(b_n\) if the digit is odd (1, 3, 5, 7, 9) and a value of 0 to \(b_n\) if the digit is even (0, 2, 4, 6, 8). This will result in a sequence of 1000 bits.
03

Compute the Average Value of b_n

Add up all values of \(b_n\) and divide the sum by 1000 to find the average value: \[ \text{average}(b_n) = \frac{1}{1000} \sum_{n=1}^{1000} b_n \].
04

Calculate Differences d_n and Their Average

Compute \(d_n = |b_{n+1} - b_n|\) for each \(n = 1, 2, \ldots, 999\). Then find the average by summing all \(d_n\) values and dividing by 999: \[ \text{average}(d_n) = \frac{1}{999} \sum_{n=1}^{999} d_n \].
05

Analyze Randomness of the Sequence

To determine if the sequence \(b_n\) appears random, check if the average value of \(b_n\) is close to 0.5, representing an equal distribution of 0s and 1s. Additionally, analyze \(d_n\); if its average is close to 0.5, it suggests random transitions between 0 and 1.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Bit Sequence
A bit sequence is a series of binary values, typically 0s and 1s, used to represent information. In this exercise, a bit sequence is constructed from the first 1000 digits of \(\pi\), which are converted into a string of bits (0s and 1s). The rule is simple: each digit of \(\pi\) is examined, and if it is odd (1, 3, 5, 7, or 9), it is represented as 1 in the bit sequence. Conversely, if the digit is even (0, 2, 4, 6, or 8), it is given the value of 0.
  • This approach transforms the non-binary \(\pi\) digits into a binary format, facilitating further analysis.
  • It is important to correctly identify each digit as odd or even, as this step is foundational.
Creating such sequences can help in various fields, such as data compression or encryption, where binary data is prevalent.
Randomness
Randomness in bit sequences refers to how unpredictable or unordered the sequence is. It's a crucial factor in determining if a sequence, like the one derived from the digits of \(\pi\), behaves like a random sequence. A sequence that is truly random should have the following characteristics:
  • The distribution of 0s and 1s should be nearly equal, so the average should be around 0.5.
  • There should be no obvious pattern in the placement of 1s and 0s.
To assess randomness, observing the average value of the bit sequence is crucial. If you're looking at the sequence of \(b_n\), and its average is near 0.5, it suggests randomness in the distribution of odd and even digits from \(\pi\). Additionally, analyzing the transition between successive bits helps to confirm randomness.
Average Value Computation
The average value of a sequence gives a central tendency or typical value for the data set. Here, it can provide insights into the nature of the bit sequence \(b_n\) and how it varies across its length. Computing this average helps us understand the balance of 1s and 0s in the sequence.
For the bit sequence \(b_n\), add up all the 1s in the sequence, then divide by 1000, the total number of digits:
\[\text{average}(b_n) = \frac{1}{1000} \sum_{n=1}^{1000} b_n\]
Similarly, for the transitions \(d_n\) (which measure changes between bits), find:
\[\text{average}(d_n) = \frac{1}{999} \sum_{n=1}^{999} d_n\]
  • If these averages approach 0.5, it indicates a balanced and likely random sequence.
  • The computations help verify the randomness and uniformity of the bit sequence.
Sequence Analysis
Sequence analysis involves looking closely at the data's structure and behavior to identify any patterns or confirm randomness. This process is crucial in understanding complex sequences derived from mathematical phenomena like \(\pi\).
  • A primary method is checking if the bit sequence \(b_n\) and the differences sequence \(d_n\) approach the expected values of 0.5.
  • Another step is observing any patterns in the transitions between bits, which could indicate non-randomness.
  • Identifying specific sections of the sequence where there are clusters of more 1s or 0s can also reveal interesting patterns.
Through this analysis, one can discern whether a sequence behaves as expected under random conditions or if it deviates, possibly due to inherent characteristics of \(\pi\) or other influences.

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