Chapter 4: Problem 48
In the following exercises, use an appropriate test to determine whether the series converges. $$ a_{k}=1 /\left(\begin{array}{l} 2 k \\ k \end{array}\right) $$
Short Answer
Expert verified
The series converges by the ratio test.
Step by step solution
01
Identify the Series
The given series has terms of the form \( a_k = \frac{1}{\binom{2k}{k}} \). We need to determine whether this series \( \sum_{k=1}^{\infty} a_k \) converges.
02
Understand the Binomial Coefficient
The binomial coefficient \( \binom{2k}{k} \) is calculated using the formula \( \binom{2k}{k} = \frac{(2k)!}{(k!)^2} \). This represents the number of ways to choose \( k \) elements from \( 2k \) elements.
03
Use Asymptotic Approximation
For large \( k \), the binomial coefficient \( \binom{2k}{k} \) is approximately \( \frac{4^k}{\sqrt{\pi k}} \). Therefore, \( a_k \approx \frac{1}{\frac{4^k}{\sqrt{\pi k}}} = \frac{\sqrt{\pi k}}{4^k} \).
04
Apply the Ratio Test
To determine convergence, apply the ratio test. Consider the ratio \( \frac{a_{k+1}}{a_k} \). Calculate it as:\[\frac{a_{k+1}}{a_k} = \frac{\sqrt{\pi(k+1)}}{4^{k+1}} \times \frac{4^k}{\sqrt{\pi k}} = \frac{\sqrt{\pi(k+1)}}{4\sqrt{\pi k}} = \frac{\sqrt{k+1}}{4\sqrt{k}} \].
05
Simplify the Ratio
Simplify \( \frac{\sqrt{k+1}}{4\sqrt{k}} \) to check its limit as \( k \to \infty \):\[\lim_{k \to \infty} \frac{\sqrt{k+1}}{4\sqrt{k}} = \lim_{k \to \infty} \frac{\sqrt{k}\sqrt{1 + \frac{1}{k}}}{4\sqrt{k}} = \lim_{k \to \infty} \frac{1}{4}\sqrt{1+\frac{1}{k}} = \frac{1}{4}.\]
06
Convergence Conclusion
Since \( \lim_{k \to \infty} \frac{\sqrt{k+1}}{4\sqrt{k}} = \frac{1}{4} < 1 \), the ratio test confirms that the series \( \sum_{k=1}^{\infty} a_k \) converges.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Ratio Test
The Ratio Test is a powerful tool used to determine whether an infinite series converges. To apply this test, you analyze the ratio of successive terms of a series. If the limit of the absolute value of the ratio of consecutive terms is less than one, the series converges. Start by considering a series in the form \( \sum_{k=1}^{\infty} a_k \). Calculate the ratio \( \frac{a_{k+1}}{a_k} \), and evaluate \( \lim_{k \to \infty} \left| \frac{a_{k+1}}{a_k} \right| \). If this limit is less than 1, the series converges absolutely. If it is greater than 1, or if it is infinite, the series diverges. If it equals 1, the test is inconclusive.
In our exercise, the ratio \( \frac{a_{k+1}}{a_k} = \frac{\sqrt{k+1}}{4\sqrt{k}} \) was calculated, and the final limit turned out to be \( \frac{1}{4} \). Since \( \frac{1}{4} < 1 \), this indicates convergence of the series \( \sum_{k=1}^{\infty} \frac{1}{\binom{2k}{k}} \). This example showcases the effectiveness of the Ratio Test in confirming convergence.
In our exercise, the ratio \( \frac{a_{k+1}}{a_k} = \frac{\sqrt{k+1}}{4\sqrt{k}} \) was calculated, and the final limit turned out to be \( \frac{1}{4} \). Since \( \frac{1}{4} < 1 \), this indicates convergence of the series \( \sum_{k=1}^{\infty} \frac{1}{\binom{2k}{k}} \). This example showcases the effectiveness of the Ratio Test in confirming convergence.
Binomial Coefficient
The binomial coefficient, denoted as \( \binom{n}{k} \), represents the number of ways to select \( k \) elements from a set of \( n \) elements without considering the order. In mathematics, it is expressed as:
In the exercise, the series uses \( \binom{2k}{k} \), calculated using \( \binom{2k}{k} = \frac{(2k)!}{(k!)^2} \). This specific binomial coefficient counts the number of ways to choose equal subsets from a larger set, a typical application in combinatorics.
Understanding the behavior and calculation of binomial coefficients allows us to simplify series expressions, as seen in the exercise where further analysis leads to applying an asymptotic approximation.
- \( \binom{n}{k} = \frac{n!}{k!(n-k)!} \)
In the exercise, the series uses \( \binom{2k}{k} \), calculated using \( \binom{2k}{k} = \frac{(2k)!}{(k!)^2} \). This specific binomial coefficient counts the number of ways to choose equal subsets from a larger set, a typical application in combinatorics.
Understanding the behavior and calculation of binomial coefficients allows us to simplify series expressions, as seen in the exercise where further analysis leads to applying an asymptotic approximation.
Asymptotic Approximation
Asymptotic approximation helps simplify complex mathematical expressions for large values of variables. When dealing with binomial coefficients such as \( \binom{2k}{k} \), exact calculations can be cumbersome, especially for large \( k \). Asymptotic approximations allow us to estimate these values more feasibly.
In the given problem, we applied the asymptotic approximation:
In the given problem, we applied the asymptotic approximation:
- \( \binom{2k}{k} \approx \frac{4^k}{\sqrt{\pi k}} \) for large \( k \)