Chapter 3: Problem 69
Find the general solution to the differential equations. $$ y^{\prime}=x^{2}+3 e^{x}-2 x $$
Short Answer
Expert verified
The general solution is \( y = \frac{x^3}{3} + 3e^x - x^2 + C \).
Step by step solution
01
Identify the Type of Differential Equation
The given differential equation is \( y' = x^2 + 3e^x - 2x \). This is a first-order differential equation and can be solved by integrating both sides.
02
Integrate to Find the General Solution
To find the general solution, integrate both sides with respect to \( x \):\[ y = \int (x^2 + 3e^x - 2x) \, dx. \]
03
Integrate Each Term Separately
Break down the integration into three terms:1. \( \int x^2 \, dx = \frac{x^3}{3} + C_1 \)2. \( \int 3e^x \, dx = 3e^x + C_2 \)3. \( \int -2x \, dx = -x^2 + C_3 \)Where \( C_1, C_2, \) and \( C_3 \) are constants of integration.
04
Combine the Integrals
Combine the integrated terms to express the general solution:\[ y = \frac{x^3}{3} + 3e^x - x^2 + C, \]where \( C = C_1 + C_2 + C_3 \) represents an arbitrary constant of integration.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
First-order Differential Equations
First-order differential equations are a fundamental type of differential equations where the highest derivative involved is the first derivative. In the context of the example given, the differential equation is presented as:
To solve such an equation, we need to integrate to find the original function \( y \). First-order differential equations can vary greatly in complexity, but this particular equation is linear in form, which allows integration as a viable method for finding solutions.
- \( y' = x^2 + 3e^x - 2x \)
To solve such an equation, we need to integrate to find the original function \( y \). First-order differential equations can vary greatly in complexity, but this particular equation is linear in form, which allows integration as a viable method for finding solutions.
Integration
Integration is a fundamental mathematical process used to find a function from its derivative. In solving differential equations like the one at hand, integrating helps us find the general solution. Given our equation:
- \( y' = x^2 + 3e^x - 2x \)
- The integral of \( x^2 \) yields \( \frac{x^3}{3} \).
- The integral of \( 3e^x \) results in \( 3e^x \).
- The integral of \( -2x \) gives \( -x^2 \).
General Solution
The term "general solution" refers to the set of all possible solutions to a differential equation. For first-order differential equations, the general solution takes into account an arbitrary constant resulting from the integration process. In our given example, integrating both sides of the equation provides:\[ y = \frac{x^3}{3} + 3e^x - x^2 + C \]Here, \( C \) represents an arbitrary constant called the constant of integration. This solution expresses \( y \) as a function of \( x \) and the constant \( C \). It illustrates how the solutions can shift vertically depending on the initial conditions or additional information provided.
The general solution is vital as it encompasses the entire family of solutions for the equation, providing us with flexibility to address specific scenarios and constraints that can come up in practical applications.
The general solution is vital as it encompasses the entire family of solutions for the equation, providing us with flexibility to address specific scenarios and constraints that can come up in practical applications.
Constants of Integration
In the process of integrating, a constant of integration arises because differentiating a constant results in zero, and thus its presence is not seen in the original derivative. In the integration of our differential equation's individual terms, you'll encounter constants like \( C_1 \), \( C_2 \), and \( C_3 \).When these are combined, as shown in the step-by-step solution, they form a single constant \( C \) in the general solution:
- \( y = \frac{x^3}{3} + 3e^x - x^2 + C \)