Chapter 3: Problem 47
For the following problems, find the general solution to the differential equation.\(y^{\prime}=4^{x}\)
Short Answer
Expert verified
The general solution is \( y(x) = \frac{4^x}{\ln 4} + C \).
Step by step solution
01
Understand the Differential Equation
You are given a first-order differential equation of the form \( y' = 4^x \). This means the derivative of \( y \) with respect to \( x \) is equal to \( 4^x \). To find the general solution, we need to integrate with respect to \( x \).
02
Set up the Integral of Both Sides
The general solution requires integrating both sides. Therefore, integrate \( \int y' \, dx = \int 4^x \, dx \). This will give us the function \( y(x) \).
03
Integrate the Right-Hand Side
The integral of \( 4^x \) with respect to \( x \) can be expressed using the formula for exponential functions: \( \int a^x \, dx = \frac{a^x}{\ln a} + C \), where \( a \) is a constant. Here, \( a = 4 \), so we have \( \int 4^x \, dx = \frac{4^x}{\ln 4} + C \).
04
Write the General Solution
After integrating, we conclude that the general solution for the differential equation is: \( y(x) = \frac{4^x}{\ln 4} + C \), where \( C \) is an arbitrary constant.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Exponential Functions
Exponential functions are mathematical expressions where a constant base is raised to a variable exponent. In our problem, the expression \( 4^x \) is an exponential function. Here, 4 is the base and \( x \) is the exponent. These functions are important in mathematics because they model a variety of real-world phenomena such as population growth, radioactive decay, and interest calculations. Key features of exponential functions include:
- Growth: When the base is greater than one, the function models exponential growth.
- Decay: When the base is between zero and one, it models exponential decay.
- Continual Change: They are used to depict how quantities grow or shrink continuously over time.
Integration Techniques
Integration is the process of finding a function, given its derivative. To solve our differential equation \( y' = 4^x \), we need to integrate both sides with respect to \( x \). This step is crucial in obtaining the function \( y(x) \) which is the solution to our differential equation.For the integration of exponential functions, we use:\[\int a^x \, dx = \frac{a^x}{\ln a} + C\]Here, \( a \) represents the base of the exponential function and \( C \) is the constant of integration. The natural logarithm \( \ln a \) appears in the denominator because derivative of \( a^x \) involves it through chain rule.Let's apply this to \( 4^x \):- Set up the integral: \( \int 4^x \, dx \)- Apply the formula: \( \int 4^x \, dx = \frac{4^x}{\ln 4} + C \)This integral gives us the function \( y(x) \) after integrating, which leads to understanding the differential equation's solutions comprehensively.
General Solution of Differential Equations
The general solution of a differential equation is a function that contains all possible solutions. For a first-order differential equation like \( y' = 4^x \), this involves integration and introducing a constant of integration denoted by \( C \). This constant represents the family of solutions, emphasizing that differential equations can have infinitely many solutions depending on initial conditions.Let's break it down:- **Differential Equation**: Our task starts with \( y' = 4^x \).- **Integrated Form**: After integrating \( 4^x \), we find \( y(x) = \frac{4^x}{\ln 4} + C \).- **Role of \( C \)**: The constant \( C \) signifies that solutions vary for different initial conditions such as \( y(x_0) = y_0 \).The expression \( y(x) = \frac{4^x}{\ln 4} + C \) encompasses all possible solutions determined by the differential equation. It is crucial to include \( C \) to represent the generality of the solution space. Understanding this concept is vital for fully capturing the behavior described by differential equations.