Chapter 3: Problem 24
The following problems add in a minimal threshold value for the species to survive, \(T\), which changes the differential equation to \(P^{\prime}(t)=r P\left(1-\frac{P}{K}\right)\left(1-\frac{T}{P}\right)\)Draw the directional field of the threshold logistic equation, assuming \(K=10, r=0.1, T=2 .\) When does the population survive? When does it go extinct?
Short Answer
Step by step solution
Understand the Directional Field
Identify Parameters
Set Up the Differential Equation
Analyze Fixed Points
Determine Stability
Sketch the Directional Field
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with Vaia!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Directional Field
For the threshold logistic equation provided, the directional field will showcase how the population changes over time, depending on its initial size. This allows us to see where the population would increase or decrease, which is incredibly useful for understanding the overall dynamics of the system.
Differential Equation
The specific differential equation in question is a threshold logistic equation, which is an extension of the standard logistic equation. It is written as: \[ P'(t) = r P \left(1 - \frac{P}{K}\right)\left(1 - \frac{T}{P}\right) \] This equation considers not only the carrying capacity but also a threshold value, altering how population growth is represented.
Population Dynamics
In this scenario, given the threshold value, populations below this threshold might shrink, risking extinction. On the other hand, populations above this threshold can grow towards the carrying capacity, stabilizing over time once they reach it.
Threshold Value
If the population size falls below this threshold, the rate of growth becomes negative, leading to a decline.
- A population size \(P < T\) could mean extinction, as seen from the test exercise.
- Conversely, when \(P > T\), the population growth may become positive, allowing the population to increase towards the carrying capacity.
Fixed Points
For the equation \[ P'(t) = 0.1 P \left(1 - \frac{P}{10}\right)\left(1 - \frac{2}{P}\right) \], the fixed points are found by solving \( P'(t) = 0 \). By doing so, we identify \( P = 0 \), \( P = 2 \), and \( P = 10 \) as fixed points. Each represents a different scenario:
- \(P = 0\): The population is extinct.
- \(P = 2\): Represents the threshold for survival.
- \(P = 10\): Represents the carrying capacity of the environment.
Stability Analysis
- At \(P = 0\), it's unstable; the population will grow if it starts above \(T\).
- At \(P = 2\), it's a stable threshold. If population reaches this point, small deviations will not cause collapse.
- At \(P = 10\), it is stable, reflecting the natural limit due to environmental resources.
This understanding helps in predicting the long-term viability of a population subject to various pressures.