Chapter 2: Problem 40
Use the trapezoidal rule with four subdivisions to estimate \(\int_{0}^{0.8} x^{3} d x\) to four decimal places.
Short Answer
Expert verified
0.1088
Step by step solution
01
Identify the interval and function
The integral provided is \[ \int_{0}^{0.8} x^{3} dx. \]The function is \( f(x) = x^3 \), and we need to evaluate this from \( x = 0 \) to \( x = 0.8 \).
02
Determine the width of each trapezoid
The interval \([0, 0.8]\) is divided into 4 equal subintervals. The width \( h \) of each subinterval is calculated as:\[ h = \frac{b - a}{n} = \frac{0.8 - 0}{4} = 0.2, \]where \( b = 0.8 \), \( a = 0 \), and \( n = 4 \).
03
Calculate function values at the endpoints and midpoints
Calculate \( f(x) \) at each endpoint:- \( f(0) = 0^3 = 0 \)- \( f(0.2) = (0.2)^3 = 0.008 \)- \( f(0.4) = (0.4)^3 = 0.064 \)- \( f(0.6) = (0.6)^3 = 0.216 \)- \( f(0.8) = (0.8)^3 = 0.512 \).
04
Apply the trapezoidal rule formula
The trapezoidal rule formula is given by:\[T = \frac{h}{2} [f(x_0) + 2(f(x_1) + f(x_2) + f(x_3)) + f(x_4)],\]where \( x_0 = 0 \), \( x_1 = 0.2 \), \( x_2 = 0.4 \), \( x_3 = 0.6 \), \( x_4 = 0.8 \).
05
Substitute values into the trapezoidal rule
Substitute the known function values into the formula:\[T = \frac{0.2}{2} [0 + 2(0.008 + 0.064 + 0.216) + 0.512].\]Calculate inside the brackets first:\[2(0.008 + 0.064 + 0.216) = 2(0.288) = 0.576.\]Thus,\[T = 0.1 [0 + 0.576 + 0.512] = 0.1 [1.088] = 0.1088.\]
06
Round to four decimal places
The calculated value of the integral using the trapezoidal rule with four decimal places is 0.1088.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Numerical Integration
Numerical integration is a powerful tool used in calculus to estimate the value of definite integrals, especially when an exact analytical solution is difficult or impossible to find. Instead of finding the antiderivative of a function, numerical methods break the problem into smaller parts and approximate the area under the curve.
One of the most widely used techniques is the trapezoidal rule. This method approximates the region under a curve by dividing it into a series of trapezoids. By calculating the areas of these trapezoids and summing them up, we obtain an estimated value for the integral.
Can't integrate complex functions easily? Here are some advantages of using numerical integration:
One of the most widely used techniques is the trapezoidal rule. This method approximates the region under a curve by dividing it into a series of trapezoids. By calculating the areas of these trapezoids and summing them up, we obtain an estimated value for the integral.
Can't integrate complex functions easily? Here are some advantages of using numerical integration:
- It handles complex, awkward functions where traditional integration fails or is tough.
- Flexibility allows for varying degrees of accuracy, depending on how much you subdivide the interval.
- It’s a foundation for more advanced methods, like Simpson's rule and Gaussian quadrature, which offer even more precision.
Approximation Methods
Approximation methods, like the trapezoidal rule, are essential in mathematics for situations where exact answers are impractical. These methods transform difficult integrals into manageable calculations. They provide a way to achieve solutions by balancing speed and accuracy.
The trapezoidal rule involves a few simple steps:
The trapezoidal rule involves a few simple steps:
- Divide the integration interval into equal sub-intervals (in this exercise, the interval is from 0 to 0.8).
- Calculate the function value at each endpoint and use these values to form trapezoids under the curve.
- Apply the trapezoidal formula to estimate the integral by summing the areas of the trapezoids.
Calculus Problem-Solving
In calculus, problem-solving often requires innovative methods to deal with complex equations and integrations. The trapezoidal rule is one such method that simplifies the process. It changes how we look at integrals by transforming them from theoretical exercises into solvable numerical problems.
For instance, in the original exercise, the trapezoidal rule was used to estimate the integral from 0 to 0.8 of the function \( x^3 \). By following systematic steps, such as dividing the interval and calculating function values, we built a practical solution.
The key to effective calculus problem-solving with these methods includes understanding the underlying mathematical principles and knowing when and how to apply them. Here are a few tips to keep in mind:
For instance, in the original exercise, the trapezoidal rule was used to estimate the integral from 0 to 0.8 of the function \( x^3 \). By following systematic steps, such as dividing the interval and calculating function values, we built a practical solution.
The key to effective calculus problem-solving with these methods includes understanding the underlying mathematical principles and knowing when and how to apply them. Here are a few tips to keep in mind:
- Always verify if the function is continuous and defined within the interval before using numerical methods.
- Consider increasing the number of sub-intervals to obtain more accurate results.
- Cross-check results with alternative methods when possible for verification.