Chapter 2: Problem 36
Use tables to evaluate the integrals. You may need to complete the square or change variables to put the integral into a form given in the table. $$ \int \frac{d x}{x^{2}+2 x+10} $$
Short Answer
Expert verified
\( \int \frac{d x}{x^{2}+2 x+10} = \frac{1}{3} \tan^{-1}\left(\frac{x+1}{3}\right) + C \).
Step by step solution
01
Recognize the Form
The integral \( \int \frac{d x}{x^{2}+2x+10} \) can potentially be evaluated using a table, but it needs to be put into a recognizable form, such as those of standard integrals. This involves completing the square for the quadratic expression \( x^2 + 2x + 10 \).
02
Complete the Square
Complete the square for the expression \( x^2 + 2x + 10 \). We do this by rewriting it as \( (x+1)^2 + 9 \). Here's the breakdown:- Take half of the coefficient of \( x \) (which is 2) and square it: \( (\frac{2}{2})^2 = 1 \).- Add and subtract this value inside the expression: \( x^2 + 2x + 1 - 1 + 10 = (x+1)^2 + 9 \).
03
Rewrite the Integral
Substitute the completed square into the integral: \( \int \frac{d x}{(x+1)^2 + 9} \).
04
Use Standard Integral Form
Recognize that this integral fits the form \( \int \frac{d x}{(x-a)^2 + b^2} = \frac{1}{b} \cdot \tan^{-1}\left(\frac{x-a}{b}\right) + C \). Here, \( a = -1 \) and \( b = 3 \).
05
Evaluate the Integral
Apply the formula: \( \int \frac{d x}{(x+1)^2 + 9} = \frac{1}{3} \tan^{-1}\left(\frac{x+1}{3}\right) + C \). This is the evaluated integral.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Completing the Square
Completing the square is a helpful algebraic technique that transforms quadratic expressions into perfect squares. This makes it easier to work with integrals involving quadratics. For instance, consider the expression \( x^2 + 2x + 10 \). We need to rewrite this in the form of \( (x+h)^2 + k \).
Here's how you can do it:
Here's how you can do it:
- Identify the coefficient of the linear term (here it's 2 in \(2x\)).
- Take half of this coefficient, which is \( \frac{2}{2} = 1 \), and square it to get 1.
- Add and subtract this squared term within the expression: \( x^2 + 2x + 1 - 1 + 10 \).
- You end up with \( (x+1)^2 + 9 \) after simplifying.
Standard Integral Forms
Standard integral forms are pre-identified patterns that provide straightforward solutions to common integral types. When integrating functions, recognizing these forms can significantly reduce complexity.
For the integral \( \int \frac{d x}{x^{2}+2x+10} \), completing the square simplified the expression into \( \int \frac{d x}{(x+1)^2 + 9} \). Here, the standard form we use is:
For the integral \( \int \frac{d x}{x^{2}+2x+10} \), completing the square simplified the expression into \( \int \frac{d x}{(x+1)^2 + 9} \). Here, the standard form we use is:
- \( \int \frac{d x}{(x-a)^2 + b^2} = \frac{1}{b} \cdot \tan^{-1}\left(\frac{x-a}{b}\right) + C \)
Calculus Problem-Solving
Calculus problem-solving often involves strategies for simplifying and transforming expressions. It requires recognizing when and how to use algebraic techniques, like completing the square, and applying formulas from a reference table of integrals.
In solving integrals like \( \int \frac{d x}{x^2 + 2x + 10} \), the problem-solving process includes:
In solving integrals like \( \int \frac{d x}{x^2 + 2x + 10} \), the problem-solving process includes:
- Transforming the quadratic expression into a complete square.
- Recognizing patterns or forms that match with standard integral formulas.
- Substituting and rearranging expressions into solvable formats.
Definite and Indefinite Integrals
Understanding the difference between definite and indefinite integrals is crucial in calculus. Both have their unique purposes and applications.
- **Definite Integrals** are used to calculate the accumulated quantity, like area under a curve, and have limits of integration (from \(a\) to \(b\)). They result in a numerical value.- **Indefinite Integrals**, on the other hand, do not have limits of integration and thus represent a family of functions, plus a constant \(C\).In the exercise we worked through, the integral \( \int \frac{d x}{x^2 + 2x + 10} \) was indefinite. The goal was to simplify and find its antiderivative, resulting in an expression \( \frac{1}{3} \tan^{-1}\left(\frac{x+1}{3}\right) + C \). This represents all possible antiderivatives of the function.
- **Definite Integrals** are used to calculate the accumulated quantity, like area under a curve, and have limits of integration (from \(a\) to \(b\)). They result in a numerical value.- **Indefinite Integrals**, on the other hand, do not have limits of integration and thus represent a family of functions, plus a constant \(C\).In the exercise we worked through, the integral \( \int \frac{d x}{x^2 + 2x + 10} \) was indefinite. The goal was to simplify and find its antiderivative, resulting in an expression \( \frac{1}{3} \tan^{-1}\left(\frac{x+1}{3}\right) + C \). This represents all possible antiderivatives of the function.