Chapter 1: Problem 33
For the following exercises, find the antiderivatives for the given functions.\(\cosh ^{2}(x) \sinh (x)\)
Short Answer
Expert verified
The antiderivative is \( \frac{\cosh^3(x)}{3} + C \).
Step by step solution
01
Identify the Integral to Solve
The task is to find the antiderivative of the function \(\cosh^2(x) \sinh(x)\). This is equivalent to integrating the function with respect to \(x\): \[ \int \cosh^2(x) \sinh(x) \, dx \]
02
Use Substitution to Simplify
To simplify the integration process, use the substitution method. Let \( u = \cosh(x) \). Then, differentiate \( u \) with respect to \( x \) to find \( du \): \[ du = \sinh(x) \, dx \] Substitute \( u \) and \( du \) into the integral:\[ \int u^2 \, du \]
03
Integrate the Simplified Expression
Now, integrate \( u^2 \) with respect to \( u \):\[ \int u^2 \, du = \frac{u^3}{3} + C \] where \( C \) is the constant of integration.
04
Substitute Back the Original Variable
Revert back to the original variable \( x \) by substituting \( u = \cosh(x) \) into the integrated result:\[ \frac{(\cosh(x))^3}{3} + C \] Thus, the antiderivative of \( \cosh^2(x) \sinh(x) \) is\[ \frac{\cosh^3(x)}{3} + C \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Hyperbolic Functions
Hyperbolic functions are analogs to the trigonometric functions we commonly know, but they are based around the hyperbola rather than the circle. The most common hyperbolic functions are the hyperbolic sine, denoted as \( \sinh(x) \), and the hyperbolic cosine, denoted as \( \cosh(x) \). These functions have profound applications in various fields like calculus, physics, and engineering.
To understand these functions better, you can relate them to their exponential form:
To understand these functions better, you can relate them to their exponential form:
- \( \sinh(x) = \frac{e^x - e^{-x}}{2} \)
- \( \cosh(x) = \frac{e^x + e^{-x}}{2} \)
Substitution Method
The substitution method is a powerful technique in calculus used to simplify integrals by introducing a new variable. This can transform a difficult or complex integral into a more manageable form.
To apply this method, follow these steps:
To apply this method, follow these steps:
- Select a substitution: In the given problem, we substitute \( u = \cosh(x) \).
- Differentiate the substitution: Find \( du \) in terms of \( dx \). In this case, \( du = \sinh(x) \, dx \).
- Rewrite the integral: Replace all instances of the original variables with the new variable \( u \). Here, \( \int \cosh^2(x) \sinh(x) \, dx \) becomes \( \int u^2 \, du \).
Integration Techniques
Integration techniques provide a toolkit for finding antiderivatives of various functions. Beyond basic rules, these techniques include substitution, integration by parts, and partial fractions.
Here, we used a basic substitution technique to evaluate \( \int u^2 \, du \). This resulted in integrating a simple polynomial:
Mastering these techniques allows one to tackle a wide range of integration problems, making them invaluable tools in both calculus and beyond.
Here, we used a basic substitution technique to evaluate \( \int u^2 \, du \). This resulted in integrating a simple polynomial:
- The antiderivative of \( u^2 \) is \( \frac{u^3}{3} + C \), where \( C \) is the integration constant.
Mastering these techniques allows one to tackle a wide range of integration problems, making them invaluable tools in both calculus and beyond.