Chapter 1: Problem 16
Use \(y=y_{0} e^{k t}\). What continuous interest rate has the same yield as an annual rate of \(9 \%\) ?
Short Answer
Expert verified
The equivalent continuous interest rate is approximately 8.62%.
Step by step solution
01
Understanding the Problem
We are asked to find the continuous interest rate equivalent to an annual interest rate of 9%. The formula given, \( y = y_0 e^{kt} \), is used to calculate continuous growth.
02
Identify Given Values
The problem indicates an annual interest rate of 9%, which is equivalent to 0.09 as a decimal. We are assuming the initial amount is \( y_0 \) and \( t = 1 \) year, since we are comparing annual rates.
03
Determine the Comparable Formula
For the annual interest rate, the corresponding expression would be \( y = y_0 (1 + r)^t \), where \( r = 0.09 \) and \( t = 1 \). This yields \( y = y_0 (1.09) \).
04
Equate Continuous and Annual Formulas
Set the continuous interest equation equal to the annual interest equation for \( t = 1 \): \[ y_0 e^{k imes 1} = y_0 (1.09) \]. This simplifies to: \[ e^{k} = 1.09 \].
05
Solve for k (the Continuous Rate)
Take the natural logarithm of both sides to solve for \( k \): \[ k = \ln(1.09) \]. Now calculate \( k \): \[ k \approx 0.0862 \].
06
Finalize the Continuous Rate
The continuous interest rate that matches an annual rate of 9% is approximately \( k = 8.62\% \). This means that if interest is compounded continuously, an annual equivalent of 9% is yielded with an 8.62% continuous rate.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Continuous Interest Rate
A continuous interest rate refers to the method of calculating interest where it is compounded continuously rather than at discrete intervals. Imagine your money growing every microsecond! This concept is built on the idea that compounding more frequently results in higher returns. The mathematical representation of continuous interest involves the exponential function. Here, the formula
- \( y = y_0 e^{kt} \)
- \( y \) is the future value of the investment.
- \( y_0 \) is the initial principal or starting amount.
- \( e \) is the base of the natural logarithm, approximately equal to 2.71828.
- \( k \) is the continuous interest rate.
- \( t \) is the time in years.
Compounded Interest
Compounded interest is simply interest on interest. Unlike simple interest, which is calculated on the principal alone, compounded interest grows on both the initial investment and any accumulated interest. This can significantly boost returns over time.
- Compounding can happen annually, semi-annually, quarterly, monthly, or even daily.
- More frequent compounding means more interest; this is where continuous compounding plays a role.
- \( y = y_0 (1 + r)^t \)
- \( y \) represents the future value.
- \( y_0 \) is the initial principal.
- \( r \) is the nominal interest rate per period.
- \( t \) is the number of periods.
Natural Logarithm
The natural logarithm is a fundamental concept in mathematics, closely connected with continuous compounding. It is the inverse of the exponential function with base \( e \). In simple terms, the natural logarithm, denoted as \( \ln(x) \), asks "to what power must \( e \) be raised, to equal \( x \)?"
- It helps in determining the time or interest rate in continuous growth scenarios.
- \( e^k = 1.09 \)
- \( k = \ln(1.09) \)