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Think About It It is known that \(y=A \sin \omega t\) is a solution of the differential equation \(y^{\prime \prime}+16 y=0 .\) Find the values of \(\omega .\)

Short Answer

Expert verified
The values for \( \omega \) are \( \pm 4 \).

Step by step solution

01

Differentiate the function once

The first derivative of the given function \(y = A \sin(\omega t)\) with respect to \(t\) is \(y' = A \omega \cos(\omega t)\). This represents the velocity of the motion at any time \(t\).
02

Differentiate the function again

The second derivative of the given function with respect to \(t\) is \(y'' = -A \omega^2 \sin(\omega t)\). This represents the acceleration of the motion at any time \(t\).
03

Substitute into the given differential equation

Now substitute \(y''\) into the given differential equation \(y'' + 16y = 0\). Substituting gives us \(-A \omega^2 \sin(\omega t) + 16A \sin(\omega t) = 0\). Simplifying yields to \(- \omega^2 + 16 = 0\).
04

Solve for \( \omega \)

To find the values of \( \omega \), solve the equation \(- \omega^2 + 16 = 0\), which results in \( \omega^2 = 16\), thus \( \omega = \pm 4\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Differential Equation Solutions
Understanding differential equations is crucial for analyzing phenomena in fields like physics and engineering. A differential equation is a mathematical equation that relates some function with its derivatives. Solving a differential equation means finding the function that satisfies the equation.

In our example, the differential equation is second-order, meaning it involves the second derivative of the function. The most common methods for solving these equations include the characteristic equation method, undetermined coefficients, or variation of parameters. It's also worth noting that differential equations can have more than one solution, often referred to as the general solution, which includes arbitrary constants that can be determined if initial conditions are known.
Sinusoidal Functions
Sinusoidal functions, such as sine and cosine, are periodic and represent oscillating motions. These functions are fundamental in modeling situations that involve repetitive patterns, like the motion of a pendulum or alternating electrical currents.

The general form of a sinusoidal function is defined as either \( A \text{sin}(\omega t + \phi) \) or \( A \text{cos}(\omega t + \phi) \) where \( A \) represents the amplitude, \( \omega \) denotes the angular frequency, \( t \) is time, and \( \phi \) is the phase shift. Understanding the properties of sinusoidal functions is key to solving differential equations that describe wave-like or harmonic motions.
Derivatives
In calculus, derivatives represent the rate at which a function is changing at any given point and are foundational to dynamic systems analysis.

The first derivative of a function gives us the velocity of an object if the function represents its position. The second derivative provides the acceleration. In our exercise, by performing the derivative of the sinusoidal function \( y = A \text{sin}(\omega t) \) twice, we identified the relationship between the function and its second derivative, which is an essential step in solving the given differential equation. Calculating derivatives is, therefore, a pivotal skill in both theoretical and applied science.
Harmonic Motion
Harmonic motion refers to a type of periodic motion where the restoring force is directly proportional to the displacement and acts in the direction opposite to that of displacement. One classic example of harmonic motion is a mass attached to a spring.

In the context of our exercise, the differential equation \( y'' + 16y = 0 \) describes a simple harmonic oscillator with no damping or external forces. The solution involves sinusoidal functions because they naturally encapsulate the properties of harmonic motion—oscillation and periodicity. Through solving the differential equation, we can understand the behavior of the system and predict its motion over time.

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Most popular questions from this chapter

Electric Circuit The diagram shows a simple electric circuit consisting of a power source, a resistor, and an inductor. A model of the current \(I,\) in amperes \((\mathrm{A}),\) at time \(t\) is given by the first-order differential equation $$L \frac{d I}{d t}+R I=E(t)$$ where \(E(t)\) is the voltage \((\mathrm{V})\) produced by the power source, \(R\) is the resistance, in ohms \((\Omega),\) and \(L\) is the inductance, in henrys \((\mathrm{H}) .\) Suppose the electric circuit consists of a \(24-\mathrm{V}\) power source, a \(12-\Omega\) resistor, and a \(4-\mathrm{H}\) inductor. (a) Sketch a slope field for the differential equation. (b) What is the limiting value of the current? Explain.

Solving a Bernoulli Differential Equation In Exercises \(59-66,\) solve the Bernoulli differential equation. The Berchoulli equation is a well-known nonlinear equation of the form $$ y^{\prime}+P(x) y=Q(x) y^{n} $$ that can be reduced to a linear form by a substitution. The general solution of a Bernoulli equation is $$ y^{1-n} e^{\int(1-n) P(x) d x}=\int(1-n) Q(x) e^{f(1-n) P(x) d x} d x+C $$ $$ y^{\prime}+3 x^{2} y=x^{2} y^{3} $$

Solving a Homogeneous Differential Equation In Exercises \(75-80\) , solve the homogeneous differential equation in terms of \(x\) and \(y .\) A homogeneous differential equation is an equation of the form \(M(x, y) d x+N(x, y) d y=0,\) where \(M\) and \(N\) are homogeneous functions of the same degree. To solve an equation of this form by the method of separation of variables, use the substitutions \(y=v x\) and \(d y=x d v+v d x\) $$ \left(x^{2}+y^{2}\right) d x-2 x y d y=0 $$

Finding a Particular Solution Using Separation of Variables In Exercises \(15-24\) , find the particular solution that satisfies the initial condition. $$ \frac{d u}{d v}=u v \sin v^{2} \quad u(0)=1 $$

Using a Logistic Differential Equation In Exercises 53 and \(54,\) the logistic differential equation models the growth rate of a population. Use the equation to (a) find the value of \(k,\) (b) find the carrying capacity, (c) graph a slope field using a computer algebra system, and (d) determine the value of \(P\) at which the population growth rate is the greatest. $$ \frac{d P}{d t}=0.1 P-0.0004 P^{2} $$

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