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Find \(d y / d x\) by implicit differentiation. \(x^{3}-3 x^{2} y+2 x y^{2}=12\)

Short Answer

Expert verified
The derivative \(dy/dx\) is \(\frac{3x^2 - 6xy - 2y^2}{3x^2 - 4xy}\).

Step by step solution

01

Differentiate Both Sides of the Equation

Differentiate the left-hand side of the equation with respect to \(x\). For terms involving \(y\), use the chain rule, i.e., first differentiate with respect to \(y\) and then multiply by \(dy/dx\). Doing this, the derivative of \(x^3\) with respect to \(x\) is \(3x^2\), of \(-3x^2y\) it is \(-3x^2dy/dx -6xy\), and of \(2xy^2\) it is \(2y^2 + 4xydy/dx\). The derivative of the right-hand side, \(12\), is \(0\). This gives us the equation \(3x^2 - 3x^2dy/dx - 6xy + 2y^2 + 4xydy/dx = 0\).
02

Rearrange the Equation

Rearrange the equation so that terms with \(dy/dx\) are on one side and terms without on the other side. This leads to \( (3x^2 - 6xy - 2y^2) = (3x^2 - 4xy) dy/dx \).
03

Solve for \(dy/dx\)

Finally, solve for \(dy/dx\), by dividing the entire equation by \(3x^2 - 4xy\), resulting in \(dy/dx = \frac{3x^2 - 6xy - 2y^2}{3x^2 - 4xy}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Calculus
Calculus is a branch of mathematics that allows us to study changes in functions. It is divided into two main parts: differential calculus and integral calculus. Differential calculus focuses on the concept of a derivative, which measures how a function changes as its input changes. This concept is crucial in understanding rates of change and slopes of curves.

Implicit differentiation, which was used in the given exercise, falls under differential calculus. It is a technique used when you have an equation that mixes dependent and independent variables, making it challenging to isolate one variable and differentiate normally. In such cases, each term of the equation is differentiated as if the dependent variable was an explicit function of the independent variable, applying appropriate differentiation rules.

For example, in the exercise given, the equation is not solved for the variable 'y', so normal differentiation is not feasible. By differentiating with respect to 'x' and treating 'y' as implicitly a function of 'x', implicit differentiation allows you to find the derivative \(d y / d x\) nonetheless.
Chain Rule
The chain rule is a powerful differentiation rule in calculus used to find the derivative of composite functions. It states that the derivative of a composite function is the derivative of the outer function evaluated at the inner function, multiplied by the derivative of the inner function.

In the context of the exercise, when you come across terms that involve both 'x' and 'y', such as \(x^2y\), where 'y' is implicitly a function of 'x', the chain rule is essential. The differentiation of such a term with respect to 'x' involves taking the partial derivative of the function with respect to 'y', and then multiplying by \(dy/dx\), the derivative of 'y' with respect to 'x'. This is what was done in the step by step solution: \( -3x^2y\) was differentiated as \( -3x^2 \cdot dy/dx - 6xy\), where \( -3x^2 \cdot dy/dx\) represents the application of the chain rule.
Derivative of an Equation
Finding the derivative of an equation involves taking the derivative of each term with respect to an independent variable — typically 'x'. When we differentiate both sides of an equation, we're applying the fundamental principle that if two expressions are equal, their derivatives are also equal. This property allows us to perform implicit differentiation, as shown in the exercise.

While differentiating each term, all the standard differentiation rules apply, such as the power rule for monomials like \(x^3\) and the product rule for products of functions like \(2xy^2\). The solution to the exercise deftly followed these procedures, determining the derivative of the left-hand side with respect to 'x', accounting for the presence of 'y' — which is treated as a function of 'x'. The derivative of the right-hand side is straightforward, as constants differentiate to zero. From there, algebraic rearrangement and solving for \(dy/dx\) yielded the final derivative of the equation.

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