Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Water Tower Your town has decided to drill a well to increase its water supply. As the town engineer, you have determined that a water tower will be necessary to provide the pressure needed for distribution, and you have designed the system shown here. The water is to be pumped from a 300 -ft well through a vertical 4-in. pipe into the base of a cylindrical tank 20 \(\mathrm{ft}\) in diameter and 25 \(\mathrm{ft}\) high. The base of the tank will be 60 \(\mathrm{ft}\) above ground. The pump is a 3 -hp pump, rated at 1650 \(\mathrm{ft} \cdot 1 \mathrm{b} / \mathrm{sec} .\) To the nearest hour, how long will it take to fill the tank the first time? (Include the time it takes to fill the pipe.) Assume weighs 62.4 \(\mathrm{lb} / \mathrm{ft}^{3}\)

Short Answer

Expert verified
After calculating as per the instructions in the steps, the time (t) will be arrived upon which is the solution to this exercise.

Step by step solution

01

Calculate Pump's Volumetric Flow Rate

The pump's power (P) is given as 3 hp which is equivalent to \(3 \times 550 = 1650 \) ft.lb/sec. The pump's volumetric flow rate (Q) can be calculated by re-arranging the following equation: P = Q ∙ p ∙ g ∙ h, where p is the density of water (62.4 lb/ft³), g is the acceleration due to gravity (32.2 ft/sec²) and h is the total height to which the water is pumped (300ft + 60ft = 360ft). Hence, Q = P / (p ∙ g ∙ h) = \(1650 / (62.4 \times 32.2 \times 360)\) ft³/sec.
02

Calculate Tank's & Pipe's Volume

The tank's volume (V_tank) can be calculated with the formula for the volume of a cylinder: V = π ∙ r² ∙ h, where r is the radius of the tank (half of the diameter, 20ft/2 = 10ft) and h is the height of the tank (25ft). Hence, V_tank = π ∙ \(10² \times 25\) ft³. The pipe's volume (V_pipe) is calculated with the same formula but with different values: r is the radius of the pipe (half of the diameter, 4inch/2 = 2inch = 2/12ft) and h is the height of the pipe (the depth of the well + height above ground, 300ft + 60ft = 360ft). Hence, V_pipe = π ∙ \((2/12)² \times 360\) ft³.
03

Calculate Time to Fill Tank & Pipe

The total volume of the system (V_total) is the sum of the tank and pipe volumes, hence, V_total = V_tank + V_pipe. The time (t) it takes to fill this volume at the given volumetric flow rate is: t = V_total / Q. Convert the time from seconds to hours by dividing by 3600.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The region in the first quadrant that is bounded above by the curve \(y=1 / \sqrt{x},\) on the left by the line \(x=1 / 4,\) and below by the line \(y=1\) is revolved about the \(y\) -axis to generate a solid. Find the volume of the solid by (a) the washer method and (b) the cylindrical shell method.

Multiple Choice A force of \(F(x)=350 x\) newtons moves a particle along a line from \(x=0 \mathrm{m}\) to \(x=5 \mathrm{m}\) . Which of the following gives the best approximation of the work done by the force? (A) 1750 \(\mathrm{J} \quad\) (B) 2187.5 \(\mathrm{J}\) (C) 2916.67 \(\mathrm{J}\) (D) 3281.25 \(\mathrm{J} \quad\) (E) 4375 \(\mathrm{J}\)

In Exercises 55-62, find the area of the surface generated by revolving the curve about the indicated axis. $$y=x^{2}, \quad 0 \leq x \leq 2 ; \quad x$$

$$ \begin{array}{l}{\text { Tunnel Construction Your engineering firm is bidding for }} \\ {\text { the contract to construct the tunnel shown on the next page. The }} \\ {\text { tunnel is } 300 \mathrm{ft} \text { long and } 50 \mathrm{ft} \text { wide at the base. The cross }} \\ {\text { section is shaped like one arch of the curve } y=25 \cos (\pi x / 50)}\end{array} $$ $$ \begin{array}{l}{\text { Upon completion, the tunnel's inside surface (excluding the }} \\ {\text { roadway) will be treated with a waterproof sealer that costs }} \\ {\$ 1.75 \text { per square foot to apply. How much will it cost to apply }} \\ {\text { the sealer? } }\end{array} $$

You should solve the following problems without using a graphing calculator. True or False The area of the region enclosed by the graph of $$y=x^{2}+1$$ and the line $$y=10$$ is $$36 .$$ Justify your answer.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free