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Multiple Choice \(\int_{0}^{2} e^{2 x} d x=\) (A) \(\frac{e^{4}}{2} \quad(\mathbf{B}) e^{4}-1 \quad\) (C) \(e^{4}-2 \quad\) (D) \(2 e^{4}-2 \quad(\mathbf{E}) \frac{e^{4}-1}{2}\)

Short Answer

Expert verified
The correct choice is (E) \(\frac{e^{4}-1}{2}\).

Step by step solution

01

Identify the Function to Integrate

Firstly, the function to integrate, \(f(x) = e^{2x}\), is given in the problem.
02

Apply the Integral Rule

Using the integral rule for \(e^{ax}\), which is \(\frac{1}{a}e^{ax}\), when a is not 0, the integral of \(e^{2x}\) is therefore \(\frac{1}{2}e^{2x}\).
03

Evaluate Definite Integral

To evaluate the definite integral, substitute the upper and lower limits, 2 and 0 respectively, into the antiderivative found in step 2. So, the result becomes \(\frac{1}{2}e^{2*2} - \(\frac{1}{2}e^{2*0}\) = \frac{1}{2}(e^{4}-1)\).

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