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In Exercises \(25-46,\) use substitution to evaluate the integral. $$\int \frac{d x}{\sqrt{5 x+8}}$$

Short Answer

Expert verified
The integral of \( \frac{1}{\sqrt{5x+8}} \) dx is \( \frac{2}{5} \sqrt{5x+8} + C \)

Step by step solution

01

Choose a new variable u

Choosing a new variable \(u\) can make the problem easier to solve. Here, let's say \(u = 5x + 8\). This makes the denominator inside the square root become \(u\). Remember to substitute \(u\) back into the integral in later steps.
02

Find du by taking derivative of u

Taking the derivative of \(u = 5x + 8\) with respect to \(x\), yields \(du = 5 dx\). We isolate \(dx\) for substitution in the integral and obtain \(dx = du/5\).
03

Substitute u and du in integral

Substituting \(u\) and \(dx\) into the original integral, we get: \(\int \frac{du/5}{\sqrt{u}}=\frac{1}{5}\int u^{-1/2} du\).
04

Evaluate the integral

Now we can evaluate the integral using the antiderivative of \(u^{-1/2}\), which is \(2u^{1/2}\). Doing so, we find the integral equals \(\frac{1}{5}(2u^{1/2}) = 2/5 \sqrt{u}\).
05

Substitute u back

Substitute \(u\) back into the equation, which we originally stated as \(u = 5x + 8\). Our final result is : \(2/5 \sqrt{5x+8}\), plus a constant, say \(C\). So, the result is \(2/5 \sqrt{5x+8}+C\).

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