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True or False If \(f^{\prime}(x)=g(x),\) then \(\int x^{2} g(x) d x=\) \(x^{2} f(x)-2 \int x f(x) d x .\) Justify your answer.

Short Answer

Expert verified
True

Step by step solution

01

Identify Function u and dv

We can set \(u=x^2\) and \(v'=g(x)\) respectively. Then calculate \(du = 2x dx\) and \(v = ∫g(x) dx = f(x)\).
02

Apply the formula of Integration by Parts

The formula \(\int u dv = u v - \int v du\) is applied here. Substituting \(u\), \(du\), \(v\) and \(dv\), we get \(\int x^2 g(x)dx = x^2 f(x) - \int f(x) * 2x dx\).
03

Confirm the Equivalent Expression

We observe that the expression on the right hand side of the equation is the same as the one provided in the question. Hence, the statement is confirmed to be true.

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