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In Exercises \(11-20,\) solve the initial value problem explicitly. $$\frac{d y}{d x}=5 \sec ^{2} x-\frac{3}{2} \sqrt{x}\( and \)y=7\( when \)x=0$$

Short Answer

Expert verified
The solution to the differential equation is y = 5tan(x) - (2/3)x^(3/2) + 7.

Step by step solution

01

Integrate both sides

Perform the integration of both sides of the initial equation ∫dy = ∫(5sec^2(x) - 3/2sqrt(x)) dx. The integral of dy will just be y, and on the other side due to being a sum of terms, each term will be integrated individually: ∫5sec^2(x)dx - ∫3/2sqrt(x) dx.
02

Simplify the RHS integral

The integral of sec^2(x) is known to be tan(x) and the integral of sqrt(x) is (2/3)x^(3/2). After performing those integrations, we get: y = 5tan(x) - (2/3)x^(3/2) + C, where C is the integration constant.
03

Apply the initial value condition and solve for C.

To find the value of the constant C, the initial condition stated in the problem that when x=0, y=7 is applied into the equation: 7 = 5tan(0) - (2/3)0^(3/2) + C. Simplifying the equation we get: 7 = C.
04

Substitute C into the equation

Substitute the constant, C=7, back into the equation from Step 2: y = 5tan(x) - (2/3)x^(3/2) + 7.

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