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In Exercises \(27-40\) , evaluate each integral using Part 2 of the Fundamental Theorem. Support your answer with NINT if you are unsure. $$\int_{1}^{32} x^{-6 / 5} d x$$

Short Answer

Expert verified
The value of the integral is \( - \frac{5}{2}\).

Step by step solution

01

Identify the integrand.

The integrand of the integral is \(x^{-6 / 5}\). This is the function that will be integrated.
02

Perform the Integration.

To integrate \(x^{-6 / 5}\), the power is increased by 1, and the new term is divided by this new power. As such, the anti-derivative of \(x^{-6 / 5}\) is \[5x^{-1/5}\].
03

Apply the Fundamental Theorem of Calculus, Part 2.

To find the definite integral from 1 to 32, subtract the antiderivative evaluated at 1 from the antiderivative evaluated at 32. This gives us the result: \[(5(32)^{-1/5}- 5(1)^{-1/5})\]
04

Simplify.

The previous calculation gives us \[ 5(2^{-1}) - 5 \]. This simplifies to \( \frac{5}{2} - 5 = - \frac{5}{2}\]

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