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In Exercises \(19-30,\) evaluate the integral using antiderivatives, as in Example \(4 .\) $$\int _ { 1 } ^ { 4 } - x ^ { - 2 } d x$$

Short Answer

Expert verified
The value of the integral \(\int _ { 1 } ^ { 4 } - x ^ { - 2 } d x\) is \(-0.75\).

Step by step solution

01

Rewrite the integral and find the antiderivative

First rewrite \(-x^{-2}\) as \(-1/x^2\), making the integral simpler to work with. The integral to find now is \(\int _ { 1 } ^ { 4 } \frac{-1}{x^{2}} dx\). The antiderivative of \(-1/x^2\) is \(1/x\).
02

Evaluate the antiderivative at the limits

Now the next step is to evaluate the antiderivative \(1/x\) at the upper limit \(4\) and at the lower limit \(1\). So, you need to find \(1/4 - 1/1\).
03

Calculate the result

Perform the above subtraction to obtain the result, which is \(-0.75\).

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