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Area If \(a\) and \(b\) are the lengths of two sides of a triangle, and \(\theta\) the measure of the included angle, the area \(A\) of the triangle is \(A=(1 / 2) a b \sin \theta,\) How is \(d A / d t\) related to \(d a / d t, d b / d t,\) and \(d \theta / d t ?\)

Short Answer

Expert verified
The rate of change of the area of the triangle with respect to time is related to the rates of changes of the lengths of the sides and the included angle by: \(dA/dt=1/2 * b * \sin(θ) * da/dt + 1/2 * a * \sin(θ) * db/dt + 1/2 * a * b * \cos(θ) * dθ/dt\)

Step by step solution

01

Write down the given formula

The area of a triangle when two sides and the enclosed angle are known can be computed with the formula: \(A=1/2 * a * b * \sin(θ)\)
02

Differentiate with respect to time

Differentiate both sides of the equation with respect to time, using the chain rule. The chain rule states that the derivative of a composite function is the derivative of the outer function multiplied by the derivative of the inner function. The result is: \(dA/dt=1/2 * (b * \sin(θ) * da/dt + a * \sin(θ) * db/dt + a * b * \cos(θ) * dθ/dt)\)
03

Simplify Result

The formula can be simplified to: \(dA/dt=1/2 * b * \sin(θ) * da/dt + 1/2 * a * \sin(θ) * db/dt + 1/2 * a * b * \cos(θ) * dθ/dt\)

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