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Multiple Choice If \(a<0,\) the graph of \(y=a x^{3}+3 x^{2}+\) \(4 x+5\) is concave up on (A) \(\left(-\infty,-\frac{1}{a}\right)\) (B) \(\left(-\infty, \frac{1}{a}\right)\) (C) \(\left(-\frac{1}{a}, \infty\right) (D) \)\left(\frac{1}{a}, \infty\right)\( (E) \)(-\infty,-1)$

Short Answer

Expert verified
The function is concave up on the interval \( \left( -1/a , \infty \right) \). So, option (C) \(\left(-\frac{1}{a}, \infty\right)\) is the correct answer.

Step by step solution

01

Find the derivative

To begin with, find the derivative of the given function. The derivative of \(y = a x^{3} + 3 x^{2} + 4 x + 5\) is \(y' = 3 a x^{2} + 6 x + 4\).
02

Find the second derivative

Next, find the second derivative, which is the derivative of the first derivative. The second derivative of y is \( y'' = 6 a x + 6 \).
03

Set the second derivative equal to zero

To find the points or intervals where the function changes concavity, set the second derivative equal to zero: \( 6 a x + 6 = 0 \) Solving for x, gives \( x = -1/a \).
04

Determine intervals of concavity

To determine where the function is concave up, evaluate the second derivative at points to the left and right of \( x = -1/a \). Since \( a < 0 \), if you test a number less than \( -1/a \), the second derivative will be negative, hence the function is concave down. And for a number greater than \( -1/a \), the second derivative will be positive meaning the function is concave up. Therefore, the function is concave up on the interval \( \left( -1/a , \infty \right) \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Second Derivative Test
The second derivative test is a convenient method to determine the concavity of a function. Concavity refers to the direction in which a function curves: upwards like a cup (concave up) or downwards like a frown (concave down).

When applying the second derivative test, you calculate the second derivative of the function and then examine its sign. A positive second derivative indicates that the function is concave up at that point, while a negative second derivative means that the function is concave down. This test is also helpful to locate points of inflection, which occur where the concavity of the function changes—that is, where the second derivative is zero or undefined.
Concave Up and Concave Down Intervals
To understand concave up and concave down intervals, imagine the graph of a function as a road. A concave up interval is where the road curves upwards, forming a valley, such that the slope of the tangent keeps increasing. Conversely, in concave down intervals, the graph forms a hill, and the slope of the tangent decreases.

These concavities are of particular interest because they tell you about the behavior of the function. A function with a graph that's concave up is one where the rate of growth is increasing; meanwhile, a graph that's concave down shows a decreasing rate of growth. Detecting these intervals involves finding the sign of the function’s second derivative over different ranges of the input variable.
Finding Derivatives
Derivatives are the fundamental tool for understanding the behavior of polynomial functions. Simply put, finding the derivative of a function gives you the rate at which the function's output changes with respect to its input. To find the derivative, you apply the rules of differentiation to each term of the function.

Power Rule for Derivatives

  • The derivative of a term like \(ax^n\) is found by bringing down the exponent as a coefficient (multiplying it by the coefficient a), and then decreasing the exponent by one.
  • For constants (terms without a variable), the derivative is zero, since they do not change as the input changes.
Once you have the first derivative, finding the second derivative involves applying the differentiation rules once more to the result.
Analyzing Function Behavior
Analyzing function behavior goes beyond just plotting the graph. It includes understanding the rate of change (first derivative), the concavity (second derivative), and even higher-order derivatives for more complex behaviors. Critical points, inflection points, increasing and decreasing intervals, and the end behavior of the function are all aspects to consider when analyzing.

By combining the information from both the first and second derivatives, you can start to paint a comprehensive picture of the function’s behavior across its domain. This includes where it's rising or falling, where it's speeding up or slowing down, and where significant changes in curvature occur. Functions also have practical implications as they can model various real-world scenarios, so analyzing their behavior is not just a mathematical exercise but also an applicable skill in various sciences.

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Most popular questions from this chapter

Motion along a Circle A wheel of radius 2 ft makes 8 revolutions about its center every second. (a) Explain how the parametric equations \(x=2 \cos \theta, \quad y=2 \sin \theta\) \(x=2 \cos \theta, \quad y=2 \sin \theta\) (b) Express \(\theta\) as a function of time \(t\) . (c) Find the rate of horizontal movement and the rate of vertical movement of a point on the edge of the wheel when it is at the position given by \(\theta=\pi / 4, \pi / 2,\) and \(\pi .\)

Approximations that Get Worse and Worse Apply Newton's method to \(f(x)=x^{1 / 3}\) with \(x_{1}=1,\) and calculate \(x_{2}\) , \(x_{3}, x_{4},\) and \(x_{5} .\) Find a formula for \(\left|x_{n}\right| .\) What happens to \(\left|x_{n}\right|\) as \(n \rightarrow \infty ?\) Draw a picture that shows what is going on.

Writing to Learn Find the linearization of \(f(x)=\sqrt{x+1}+\sin x\) at \(x=0 .\) How is it related to the individual linearizations for \(\sqrt{x+1}\) and \(\sin x ?\)

In Exercises 62 and \(63,\) feel free to use a CAS (computer algebra system), if you have one, to solve the problem. Logistic Functions Let \(f(x)=c /\left(1+a e^{-h x}\right)\) with \(a>0\) \(a b c \neq 0\) (a) Show that \(f\) is increasing on the interval \((-\infty, \infty)\) if \(a b c>0\) and decreasing if \(a b c<0\) . (b) Show that the point of inflection of \(f\) occurs at \(x=(\ln |a|) / b\)

Analyzing Derivative Data Assume that \(f\) is continuous on \([-2,2]\) and differentiable on \((-2,2) .\) The table gives some values of \(f^{\prime}(x)\) $$ \begin{array}{cccc}\hline x & {f^{\prime}(x)} & {x} & {f^{\prime}(x)} \\\ \hline-2 & {7} & {0.25} & {-4.81} \\ {-1.75} & {4.19} & {0.5} & {-4.25} \\\ {-1.5} & {1.75} & {0.75} & {-3.31} \\ {-1.25} & {-0.31} & {1} & {-2}\end{array} $$ $$ \begin{array}{rrrr}{-1} & {-2} & {1.25} & {-0.31} \\ {-0.75} & {-3.31} & {1.5} & {1.75} \\ {-0.5} & {-4.25} & {1.75} & {4.19}\end{array} $$ $$ \begin{array}{cccc}{-0.25} & {-4.81} & {2} & {7} \\ {0} & {-5}\end{array} $$ $$ \begin{array}{l}{\text { (a) Estimate where } f \text { is increasing, decreasing, and has local }} \\ {\text { extrema. }} \\ {\text { (b) Find a quadratic regression equation for the data in the table }} \\ {\text { and superimpose its graph on a scatter plot of the data. }} \\ {\text { (c) Use the model in part (b) for } f^{\prime} \text { and find a formula for } f \text { that }} \\ {\text { satisties } f(0)=0 .}\end{array} $$

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