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Multiple Choice Two positive numbers have a sum of 60. What is the maximum product of one number times the square of the second number? (a) 3481 (b) 3600 (c) 27,000 (d) 32,000 (e) 36,000

Short Answer

Expert verified
The maximum product of one number times the square of the second number is 0.

Step by step solution

01

Define Variables

Let's define the two numbers as x and (60-x), since they have to add up to 60.
02

Create an Equation

a function f(x) which represents the product of one number and the square of the other, can be written as \(f(x) = x * (60 - x)^2\).
03

Differentiate the Function

Differentiate the function \(f(x)\) to get \(f'(x)\) = \(2x(60 -x) - (60-x)^2 = 120x - 3x^2 -3600 +120x = 240x - 3x^2 - 3600\). Set the derivative equal to zero to find the maximum and minimum points on the function.
04

Solve for x

Solving the derivative \(240x - 3x^2 - 3600 = 0\) gives \(x = 20, 60\). A second derivative test will indicate which of these x-values gives maximum product.
05

Second Derivative Test

Second derivative of the function is \(f''(x) = 240 - 6x\). Evaluating \(f''(20) = 240 - 120 = 120\) and \(f''(60) = 240 - 360 = -120\). Since \(f''(60) < 0\), x = 60 yields a maximum product.
06

Evaluate the Maximum Product

Substitute x = 60 into the original function, \(f(60) = 60 * (60 - 60)^2 = 0\). So, the maximum product of one number times the square of the other is 0.

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