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The domain of f^{\prime}\( is \)[0,1) \cup(1,2) \cup(2,3]

Short Answer

Expert verified
The domain of \(f^{\prime}\) is from 0 to 3, excluding 1 and 2, but including 0 and 3.

Step by step solution

01

Understand Interval Notation

In mathematics, an interval is a set of real numbers with the property that any number that lies between two numbers in the set is also included in the set. For example, the interval \([0,1)\) includes all numbers between 0 and 1, but does not include 1 itself. This is because of the parenthesis around 1. If it were a square bracket like around 0, it would include the 1.
02

Break Down the Domain

The given domain is comprised of three intervals, which are: \([0,1)\), \((1,2)\), and \((2,3]\). This means that \(f^{\prime}\) is defined for all numbers between 0 and 1, not including 1, all numbers between 1 and 2, not including 1 and 2, and all numbers between 2 and 3, including the 3.
03

Write Entire Domain

Taking all of this into consideration, the domain for \(f^{\prime}\) is all the numbers from 0 to 3, excluding 1 and 2 but including 0 and 3.

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