Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Expanding Circle The radius of a circle is increased from 2.00 to 2.02 \(\mathrm{m} .\) (a) Estimate the resulting change in area. (b) Estimate as a percentage of the circle's original area.

Short Answer

Expert verified
The area of the circle increased by approximately \(0.0804π square meters\) or about 2.01%.

Step by step solution

01

Calculate original area

First, let's calculate the original area of the circle with a radius of 2.00 m using the formula \(A = πr^2\). The original area \(A_1\) then becomes \(A_1 = π(2.00^2) = 4π square meters.\)
02

Calculate new area

Next, let's calculate the new area of the circle with a radius of 2.02 m using the formula \(A = πr^2\). The new area \(A_2\) then becomes \(A_2 = π(2.02^2) = 4.0804π square meters.\)
03

Calculate the change in area

The change in area (\(ΔA\)) is new area minus original area, that is, \(ΔA = A_2 - A_1 = 4.0804π - 4π = 0.0804π square meters.\)
04

Calculate the percentage change

The percentage change in area can be calculated using the formula \((\Delta A / A_1) * 100\). Therefore, the percentage change is \((0.0804π / 4π) * 100 = 2.01%.\)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free