Chapter 4: Problem 45
Connecting \(f\) and \(\boldsymbol{f}^{\prime}\) Sketch a smooth curve \(y=f(x)\) through the origin with the properties that \(f^{\prime}(x)<0\) for \(x<0\) and \(f^{\prime}(x)>0\) for \(x>0\)
Chapter 4: Problem 45
Connecting \(f\) and \(\boldsymbol{f}^{\prime}\) Sketch a smooth curve \(y=f(x)\) through the origin with the properties that \(f^{\prime}(x)<0\) for \(x<0\) and \(f^{\prime}(x)>0\) for \(x>0\)
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Get started for freeTrue or False If \(f^{\prime}(c)=0\) and \(f^{\prime \prime}(c)<0,\) then \(f(c)\) is a local maximum. Justify your answer.
\(f\) is an even function, continuous on \([-3,3],\) and satisfies the following. (d) What can you conclude about \(f(3)\) and \(f(-3) ?\)
The Linearization is the Best Linear Approximation Suppose that \(y=f(x)\) is differentiable at \(x=a\) and that \(g(x)=m(x-a)+c(m\) and \(c\) constants). If the error \(E(x)=f(x)-g(x)\) were small enough near \(x=a,\) we might think of using \(g\) as a linear approximation of \(f\) instead of the linearization \(L(x)=f(a)+f^{\prime}(a)(x-a) .\) Show that if we impose on \(g\) the conditions i. \(E(a)=0\) ii. \(\lim _{x \rightarrow a} \frac{E(x)}{x-a}=0\) then \(g(x)=f(a)+f^{\prime}(a)(x-a) .\) Thus, the linearization gives the only linear approximation whose error is both zero at \(x=a\) and negligible in comparison with \((x-a)\) .
Multiple Choice A cylindrical rubber cord is stretched at a constant rate of 2 \(\mathrm{cm}\) per second. Assuming its volume does no change, how fast is its radius shrinking when its length is 100 \(\mathrm{c}\) and its radius is 1 \(\mathrm{cm} ?\) $$\begin{array}{ll}{\text { (A) } 0 \mathrm{cm} / \mathrm{sec}} & {\text { (B) } 0.01 \mathrm{cm} / \mathrm{sec}} 67 {\text{ (C) } 0.02 \mathrm{cm} / \mathrm{sec}}$\\\ {\text { (D) } 2 \mathrm{cm} / \mathrm{sec}} & {\text { (E) } 3.979 \mathrm{cm} / \mathrm{sec}}\end{array}
Multiple Choice The \(x\) -coordinates of the points of inflection of the graph of \(y=x^{5}-5 x^{4}+3 x+7\) are \(\mathrm \) (A) 0 only (B) 1 only (C) 3 only (D) 0 and 3 (E) 0 and 1
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