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True or False \(\frac{d}{d x}(\sin x)=\cos x,\) if \(x\) is measured in degrees or radians. Justify your answer.

Short Answer

Expert verified
False. The derivative of \( \sin x \) with respect to \( x \) is \( \cos x \) when \( x \) is measured in radians, and \( \frac{\pi}{180} \cos x \) when \( x \) is measured in degrees.

Step by step solution

01

Understand the derivative in radians

The derivative of \( \sin x \) with respect to \( x \) is \( \cos x \) when \( x \) is measured in radians. This is a fundamental rule in calculus. This can be proven using limits definition of derivatives.
02

Understand the derivative in degrees

When \( x \) is measured in degrees, the situation changes. Degrees and radians are just different units for measuring angles, like inches and centimeters are different units for measuring length. There's a conversion factor between the two, specifically, \( \pi \) radians is the same as 180 degrees. Therefore, when we're taking the derivative of \( \sin x \) where \( x \) is measured in degrees, it's like we're measuring in radians but with a conversion factor. This results in the derivative being \( \cos x \) times the conversion factor from degrees to radians, which is \( \frac{\pi}{180} \). This is because the Chain rule in derivatives states that if you have a function inside another function, the derivative is the derivative of the outer function times the derivative of the inner function.
03

Conclusion

Therefore, the derivative of \( \sin x \) with respect to \( x \) is not just \( \cos x \) when \( x \) is measured in degrees. It's \( \frac{\pi}{180} \cos x \). So, the statement is false when \( x \) is measured in degrees.

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Most popular questions from this chapter

Volcanic Lava Fountains Although the November 1959 Kilauea Iki eruption on the island of Hawaii began with a line of fountains along the wall of the crater, activity was later confined to a single vent in the crater's floor, which at one point shot lava 1900 ft straight into the air (a world record). What was the lava's exit velocity in feet per second? in miles per hour? [Hint: If \(v_{0}\) is the exit velocity of a particle of lava, its height \(t\) seconds later will be \(s=v_{0} t-16 t^{2}\) feet. Begin by finding the time at which \(d s / d t=0 .\) Neglect air resistance.

Radians vs. Degrees What happens to the derivatives of \(\sin x\) and cos \(x\) if \(x\) is measured in degrees instead of radians? To find out, take the following steps. (a) With your grapher in degree mode, graph \(f(h)=\frac{\sin h}{h}\) and estimate \(\lim _{h \rightarrow 0} f(h) .\) Compare your estimate with \(\pi / 180 .\) Is there any reason to believe the limit should be \(\pi / 180 ?\) (b) With your grapher in degree mode, estimate \(\lim _{h \rightarrow 0} \frac{\cos h-1}{h}\) (c) Now go back to the derivation of the formula for the derivative of sin \(x\) in the text and carry out the steps of the derivation using degree-mode limits. What formula do you obtain for the derivative? (d) Derive the formula for the derivative of cos \(x\) using degree-mode limits. (e) The disadvantages of the degree-mode formulas become apparent as you start taking derivatives of higher order. What are the second and third degree-mode derivatives of \(\sin x\) and \(\cos x\) ?

You may use a graphing calculator to solve the following problems. True or False The domain of \(y=\sin ^{-1} x\) is \(-1 \leq x \leq 1\) . Justify your answer.

Multiple Choice Which of the following is equal to \(d y / d x\) if \(y=x^{3 / 4} ?\) (a) $$\frac{3 x^{1 / 3}}{4} \quad\left(\text { B) } \frac{4 x^{1 / 4}}{3}\right.$$ (c) $$\frac{3 x^{1 / 4}}{4} \quad(\mathbf{D}) \frac{4}{3 x^{1 / 4}}$$ (E) \(\frac{3}{4 x^{1 / 4}}\)

Multiple Choice Which of the following is \(\frac{d}{d x} \tan ^{-1}(3 x) ?\) \((\mathbf{A})-\frac{3}{1+9 x^{2}} \quad(\mathbf{B})-\frac{1}{1+9 x^{2}} \quad\) (C) \(\frac{1}{1+9 x^{2}}\) \((\mathbf{D}) \frac{3}{1+9 x^{2}} \quad(\mathbf{E}) \frac{3}{\sqrt{1-9 x^{2}}}\)

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