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Let \(y=x^{2}+7 x-5 .\) Evaluate \(d y / d t\) when \(x=1\) and \(d x / d t=1 / 3\)

Short Answer

Expert verified
The derivative \(dy/dt\) when \(x=1\) and \(dx/dt=1/3\) is 3.

Step by step solution

01

Differentiate y with respect to x

Using the power rule of differentiation, which states that the derivative of \(x^n\) with respect to x is \(nx^{n-1}\), we get: \(\frac{dy}{dx} = 2x + 7.\)
02

Substitute x = 1 into the equation

Substitute \(x = 1\) into \(\frac{dy}{dx}\) equation to find \(\frac{dy}{dx}\) at \(x = 1.\) So, we have \(\frac{dy}{dx}(1) = 2(1) + 7 = 9.\)
03

Apply the chain rule

Apply the chain rule. According to the formula \(dy/dt = (dy/dx)•(dx/dt)\), substituting in \(\frac{dy}{dx} = 9\) (from Step 2) and \(dx/dt = 1/3\) (according to the problem), this gives \(dy/dt = 9 * 1/3 = 3.\)

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