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Multiple Choice Which of the following is the measure of \(\tan ^{-1}(-\sqrt{3})\) in degrees? \(\begin{array}{llll}{\text { (A) }-60^{\circ}} & {\text { (B) }-30^{\circ}} & {\text { (C) } 30^{\circ}} & {\text { (D) } 60^{\circ}} & {\text { (E) } 120^{\circ}}\end{array}\)

Short Answer

Expert verified
-60 degrees

Step by step solution

01

Identify the value of the inverse tangent

The value we're interested in is \(\tan^{-1}(-\sqrt{3})\). This refers to the angle whose tangent is -√3.
02

Recall tangent values

Remember the tangent values for common angles. The tangent of 60 degrees is √3, and the tangent of -60 degrees is -√3.
03

Choose the correct answer

The angle whose tangent is -√3 is -60 degrees. Therefore, \(\tan^{-1}(-\sqrt{3})\) is -60 degrees.

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Most popular questions from this chapter

Multiple Choice Which of the following gives the domain of \(f(x)=\frac{x}{\sqrt{9-x^{2}}}\) \(\begin{array}{ll}{\text { (A) } x \neq \pm 3} & {\text { (B) }(-3,3)} \\\ {(\mathrm{D})(-\infty,-3) \cup(3, \infty)} & {(\mathrm{E})(3, \infty)}\end{array}\)

Multiple Choice The length \(L\) of a rectangle is twice as long as its width \(W\) . Which of the following gives the area \(A\) of the rectangle as a function of its width? $$(a)A(W)=3 W \quad$$ $$(b)A(W)=\frac{1}{2} W^{2} \quad(\mathbf{C}) A(W)=2 W^{2}$$ $$(\mathbf{D}) A(W)=W^{2}+2 W \quad(\mathbf{E}) A(W)=W^{2}-2 W$$

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