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In Exercises \(21-30\) , determine whether the function is even, odd, or neither. Try to answer without writing anything (except the answer). $$y=\frac{1}{x^{2}-1}$$

Short Answer

Expert verified
The function \(y=\frac{1}{x^{2}-1}\) is even.

Step by step solution

01

The Original Function

We start with the original function which is \(y= \frac{1}{x^{2}-1}\).
02

Calculate \(f(-x)\)

Plug in \(-x\) for \(x\) in the formula, to get \(f(-x)= \frac{1}{(-x)^{2}-1}\).
03

Simplify \(f(-x)\)

Simplify the formula for \(f(-x)\), because we know that \((-x)^2 = x^2\) we simplify \(f(-x)\) to \(f(-x)= \frac{1}{x^{2}-1}\).
04

Compare \(f(x)\) and \(f(-x)\)

Compare \(f(x)\) and \(f(-x)\). They are the same, so \(f(x) = f(-x)\). This means the function is even.

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