Chapter 8: Problem 22
Evaluate each improper integral or show that it diverges. \(\int_{1}^{\infty} \operatorname{csch} x d x\)
Short Answer
Expert verified
The integral converges to \(-\ln |\tanh(1/2)|\).
Step by step solution
01
Identify the Improper Integral
The given integral is \( \int_{1}^{\infty} \operatorname{csch} x \, dx \). Since the upper limit of integration is infinity, this is an improper integral. To evaluate it, we first rewrite it as a limit: \( \lim_{b \to \infty} \int_{1}^{b} \operatorname{csch} x \, dx \).
02
Find the Antiderivative of \( \operatorname{csch} x \)
The function \( \operatorname{csch} x = \frac{1}{\sinh x} \). The function \( \sinh x \) is an odd function related to hyperbolic sine, with the property that its derivative is \( \cosh x \). However, directly integrating \( \operatorname{csch} x \) involves using substitution or recognizing it in terms of known integrals, where \( \int \operatorname{csch} x \ dx = \ln |\tanh(x/2)| + C \).
03
Evaluate the Definite Integral
Using the antiderivative from Step 2, evaluate the definite integral from 1 to \( b \): \( \int_{1}^{b} \operatorname{csch} x \, dx = \left[ \ln |\tanh(x/2)| \right]_{1}^{b} = \ln |\tanh(b/2)| - \ln |\tanh(1/2)| \).
04
Take the Limit as \( b \to \infty \)
Take the limit of the expression \( \ln |\tanh(b/2)| - \ln |\tanh(1/2)| \) as \( b \to \infty \). As \( x \to \infty \), \( \tanh(x/2) \to 1 \), meaning \( \ln |\tanh(b/2)| \to \ln 1 = 0 \). Thus, the expression approaches \( 0 - \ln |\tanh(1/2)| \).
05
Analyze Convergence
Since the integral evaluates to \( -\ln |\tanh(1/2)| \), which is a finite number, the improper integral \( \int_{1}^{\infty} \operatorname{csch} x \, dx \) converges.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Hyperbolic Functions
Hyperbolic functions are similar to trigonometric functions but are based on hyperbolas instead of circles. One of the functions most commonly encountered in calculus is the hyperbolic sine function, denoted as \( \sinh(x) \). The hyperbolic cosecant function \( \operatorname{csch}(x) \) is defined as the reciprocal of \( \sinh(x) \):
- \( \operatorname{csch}(x) = \frac{1}{\sinh(x)} \)
- \( \sinh(x) = \frac{e^x - e^{-x}}{2} \)
- \( \sinh(x) \) is an odd function, just like \( \sin(x) \).
- Its derivative, \( \cosh(x) \), is similar to \( \cos(x) \). It is worth noting that the integral of \( \operatorname{csch}(x) \) involves unique results such as \( \ln |\tanh(x/2)| + C \).
Convergence of Integrals
When we talk about convergence in the context of improper integrals, we refer to whether the integral has a finite value over an infinite interval. The integral \( \int_{1}^{\infty} \operatorname{csch}(x) \, dx \) is an improper integral because it extends to infinity.To evaluate an improper integral, we must perform a limit process. This often means converting the integral to a limit of finite integrals as some boundary approaches infinity. For example:
- \( \lim_{b \to \infty} \int_{1}^{b} \operatorname{csch} x \, dx \)
Integration Techniques
Integration techniques encompass various methods to find antiderivatives or evaluate definite integrals. When dealing with functions like \( \operatorname{csch}(x) \), recognizing it as the reciprocal of \( \sinh(x) \) is the first step.Some techniques useful in integration include:
- Substitution: Useful when an integral contains a composite function. It can simplify the integral by substituting variables to reduce complexity.
- Integration by Parts: This technique is helpful when the integral is the product of functions and can be simplified by distributing differentiation and integration tasks across these functions.