Chapter 7: Problem 8
Plot a slope field for each differential equation. Use the method of separation of variables (Section 4.9) or an integrating factor (Section 7.7) to find a particular solution of the differential equation that satisfies the given initial condition, and plot the particular solution. $$ y^{\prime}=-y ; y(0)=4 $$
Short Answer
Step by step solution
Understanding the Differential Equation
Separation of Variables
Integrating Both Sides
Solving for \( y \)
Apply the Initial Condition
Plotting the Slope Field
Plotting the Particular Solution
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Slope Field
This means all slopes in the field depend solely on the \( y \)-value, not \( x \). For instance, when \( y = 2 \), the slope is \(-2\) regardless of the \( x \)-coordinate. Slope fields help us visualize the direction that solutions to the differential equation will follow.
By plotting a slope field, you can see the general shape and behavior of solutions, and how they might change with different initial conditions. It's like a road map for finding solutions without actually solving the equation.
Separation of Variables
This step is crucial because it allows us to integrate both sides independently: the left side with respect to \( y \) and the right side with respect to \( x \).
Once the equation is separated, the integration process reveals the natural logarithm on the left side: \( \ln|y| \) and a linear term on the right: \(-x + C\) (where \( C \) is the integration constant).
This method is particularly useful because it simplifies the process of solving differential equations by reducing it to straightforward integration.
Initial Condition
Initial conditions are essential because they allow us to pinpoint the exact solution from a family of solutions.
Without an initial condition, a differential equation can often have many solutions, differing by a constant. Applying \( y(0) = 4 \) to the general solution \( y = Ce^{-x} \) helps us find the particular solution by determining the constant \( C \). It turns out \( C \) equals 4 in our specific case, so our particular solution becomes \( y = 4e^{-x} \). This solution is plotted on the slope field to show how it follows the directions indicated by the slopes, starting from the initial point.
Particular Solution
We found that, using the initial condition \( y(0) = 4 \), \( C = 4 \). Thus, the particular solution is \( y = 4e^{-x} \).
This solution not only satisfies the differential equation but also adheres to the initial condition provided. The particular solution is critical because it represents the actual scenario from the range of potential behaviors indicated by the slope field.
When plotted on the same graph as the slope field, the particular solution gives a path that accurately tracks from the initial value through each point, reflecting the flow of the slope field.