Question

Find the length of the indicated curve. \(y=\cosh x\), between \(x=0\) and \(x=4\)

Short answer

The length of the curve is approximately 27.29.

Step-by-step solution

Recall the formula for arc length

The formula to find the arc length of a curve given by a function \(y = f(x)\) from \(x = a\) to \(x = b\) is \( L = \int_{a}^{b} \sqrt{1 + \left( \frac{dy}{dx} \right)^2} \, dx \). For our problem, \(a = 0\) and \(b = 4\).

Differentiate the function

Find \( \frac{dy}{dx} \) for \( y = \cosh x \). The derivative \( \frac{dy}{dx} = \sinh x \) since the derivative of \( \cosh x \) is \( \sinh x \).

Substitute into the arc length formula

The arc length formula becomes \( L = \int_{0}^{4} \sqrt{1 + (\sinh x)^2} \, dx \).

Simplify the integrand

Use the identity \( \cosh^2 x - \sinh^2 x = 1 \) to simplify \( \sqrt{1 + \sinh^2 x} \). It becomes \( \sqrt{\cosh^2 x} \), which simplifies to \( \cosh x \) since \( \cosh x > 0 \) for all \(x\).

Set up the integral

The integral now is \( L = \int_{0}^{4} \cosh x \, dx \).

Compute the integral

Integrate \( \cosh x \) to get \( L = [\sinh x]_{0}^{4} \).

Evaluate the definite integral

Substitute the limits into the integral result: \( L = \sinh(4) - \sinh(0) \).

Calculate the values

Calculate \( \sinh(4) = \frac{e^4 - e^{-4}}{2} \) and \( \sinh(0) = 0 \). Therefore, \( L = \sinh(4) \approx 27.2899 \).

Conclusion

The length of the curve \( y = \cosh x \) from \( x = 0 \) to \( x = 4 \) is approximately 27.29.

Key concepts

Hyperbolic Functions

Hyperbolic functions are analogs to the trigonometric functions but for the hyperbola, just as trigonometric functions relate to the circle. The two primary hyperbolic functions are the hyperbolic sine, \( \sinh x \), and the hyperbolic cosine, \( \cosh x \). These functions have similar properties to sine and cosine, yet they involve exponential functions:

• \( \sinh x = \frac{e^x - e^{-x}}{2} \)
• \( \cosh x = \frac{e^x + e^{-x}}{2} \)

One fundamental identity, similar to the Pythagorean identity for sine and cosine, is \( \cosh^2 x - \sinh^2 x = 1 \). This identity was pivotal in simplifying the original arc length problem. Hyperbolic functions are used in many areas of calculus, especially where growth rates and curves are essential, such as in hyperbolic geometry and engineering scenarios. They are also invaluable in solving certain types of differential equations.

Definite Integral

The definite integral allows you to calculate the accumulation of quantities, like areas under a curve. It is expressed as \( \int_{a}^{b} f(x) \, dx \), where \( f(x) \) is your function and \( a \) and \( b \) are the limits of integration. With definite integrals, you get a specific numerical value, representing the accumulated area or "net change."
In the context of finding the arc length of the curve \( y = \cosh x \) from \( x = 0 \) to \( x = 4 \), the definite integral is used to sum up infinitely small line segments along the curve. The specific integral used was \( \int_{0}^{4} \cosh x \, dx \), which gave the total length of the hyperbolic cosine curve over the interval. This provides a real-world application of definite integrals in calculating lengths, areas, and other extensive properties.

Derivative Calculus

Derivative calculus is all about understanding how a function changes. It involves taking the derivative, which tells you the slope or rate of change at any point in the function. For \( y = \cosh x \), the derivative \( \frac{dy}{dx} \) is \( \sinh x \).
This is because the derivative of \( \cosh x \) naturally leads to \( \sinh x \). Derivatives are essential for finding instantaneous rates of change and are crucial in the formula for calculating arc length, as in the given problem. Here, knowing the derivative \( \sinh x \) was a key step before substituting into the arc length formula. Derivatives help in understanding the overarching behavior of functions, whether they are increasing, decreasing, or constant over certain intervals.

Calculus Identities

Calculus identities are fundamental equations that hold true for all variables involved and form the backbone of many calculations. An example is the identity \( \cosh^2 x - \sinh^2 x = 1 \), which is particularly useful when working with hyperbolic functions. This identity was used to simplify the expression under the integral in the arc length problem.
In calculus, such identities save time and make for more efficient problem-solving by reducing complex expressions into simpler forms. These include Pythagorean identities for trigonometric functions, basic derivatives and integrals, and hyperbolic identities, among others. Understanding these identities is essential as they frequently appear in exams and practical applications, facilitating easier manipulation and integration of functions. Identifying and effectively using calculus identities often simplifies the underlying mathematics, allowing one to focus on the broader problem at hand.