Chapter 5: Problem 35
use the Substitution Rule for Definite Integrals to evaluate each definite integral. $$ \int_{0}^{1}\left(x^{2}+1\right)^{10}(2 x) d x $$
Short Answer
Expert verified
The value of the definite integral is \(\frac{2047}{11}\).
Step by step solution
01
Identify the Inner Function for Substitution
Let's choose the inner function of the composite function as our substitution variable. In this case, the inner function is \(u = x^2 + 1\).
02
Differentiate the Substitution Variable
Differentiate \(u = x^2 + 1\) with respect to \(x\). This yields \(\frac{du}{dx} = 2x\). Therefore, \(du = 2x \cdot dx\).
03
Change the Limits of Integration
Since \(u = x^2 + 1\), substitute the limits of integration. When \(x = 0\), \(u = 0^2 + 1 = 1\), and when \(x = 1\), \(u = 1^2 + 1 = 2\). Thus, the new limits of integration for \(u\) are from 1 to 2.
04
Perform the Integration in Terms of \(u\)
Rewrite the integral in terms of \(u\) and \(du\):\[\int_{1}^{2} u^{10} \, du\].Now, use the power rule for integration: \(\int u^n \, du = \frac{u^{n+1}}{n+1} + C\). Thus, \[ \int u^{10} \, du = \frac{u^{11}}{11} \].
05
Evaluate the Integral with New Limits
Now, evaluate \(\frac{u^{11}}{11}\) from 1 to 2:\[\left[\frac{2^{11}}{11} - \frac{1^{11}}{11}\right] = \frac{2048}{11} - \frac{1}{11} = \frac{2047}{11}.\]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Inner Function Substitution
When solving integrals using the substitution rule, one of the first tasks is identifying the inner function. This refers to a function within another function (often called a composite function).
In our problem, the composite function is \( (x^2 + 1)^{10} \).
Recognizing \( x^2 + 1 \) as the inner function simplifies the integration process by setting it equal to a new variable \( u \).
In our problem, the composite function is \( (x^2 + 1)^{10} \).
Recognizing \( x^2 + 1 \) as the inner function simplifies the integration process by setting it equal to a new variable \( u \).
- Identify the component of the function that can be isolated.
- It should be simple to differentiate.
- This variable substitution helps in transforming the integral into a simpler form.
Differentiating Substitution Variable
After choosing the inner function, the next step is to differentiate it with respect to \( x \).
This means finding how changes in \( x \) affect \( u \).
For \( u = x^2 + 1 \), differentiating gives \( \frac{du}{dx} = 2x \).
This means finding how changes in \( x \) affect \( u \).
For \( u = x^2 + 1 \), differentiating gives \( \frac{du}{dx} = 2x \).
- The result is simplified to \( du = 2x \, dx \)
- This calculation is crucial as it links \( du \)and \( dx \)
- Ensure the entire differential \( dx \)is expressed in terms of \( du \)
Changing Limits of Integration
Changing the limits of integration is an integral part of substitution. Since you're using a new variable, \( u \), the original limits in terms of \( x \)must also be converted.
In our example:
This step ensures that the integral evaluation bounds correspond with the transformed function, allowing correct computation within the new variable's domain.
In our example:
- When \( x = 0 \), compute \( u = 0^2 + 1 = 1 \)
- When \( x = 1 \), compute \( u = 1^2 + 1 = 2 \)
This step ensures that the integral evaluation bounds correspond with the transformed function, allowing correct computation within the new variable's domain.
Power Rule for Integration
The power rule for integration is a fundamental principle that allows you to integrate expressions of the form \( u^n \).
This rule states that \( \int u^n \, du = \frac{u^{n+1}}{n+1} + C \).Applying this rule:
Plug in the limits to get the exact numerical result: \( \left[\frac{2^{11}}{11} - \frac{1^{11}}{11}\right] = \frac{2048}{11} - \frac{1}{11} = \frac{2047}{11} \).
Practicing the power rule ensures a streamlined process for integrating polynomials and similar power functions.
This rule states that \( \int u^n \, du = \frac{u^{n+1}}{n+1} + C \).Applying this rule:
- Use it on the integral \( \int_{1}^{2} u^{10} \, du \)
- Apply it yielding \( \frac{u^{11}}{11} \)
- No constant needed since we're evaluating definite integrals
Plug in the limits to get the exact numerical result: \( \left[\frac{2^{11}}{11} - \frac{1^{11}}{11}\right] = \frac{2048}{11} - \frac{1}{11} = \frac{2047}{11} \).
Practicing the power rule ensures a streamlined process for integrating polynomials and similar power functions.