Chapter 3: Problem 55
Express the indicated derivative in terms of the function \(F(x) .\) Assume that \(F\) is differentiable. $$ D_{x} \tan F(2 x) $$
Short Answer
Expert verified
\(\sec^2(F(2x)) \cdot F'(2x) \cdot 2\)
Step by step solution
01
Identify the function and its components
The expression gives us the derivative of a composite function. We have \(\tan F(2x)\). This involves an outer function (\(\tan u\)) and an inner composite function (\(F(2x)\)).
02
Apply the chain rule
To find the derivative of \(\tan F(2x)\), we apply the chain rule. The chain rule states that if you have a composite function \(u(v(x))\), its derivative is: \((d/dx) u(v(x)) = u'(v(x)) \cdot v'(x)\).
03
Differentiate the outer function
The outer function is \(\tan u\), whose derivative is \((\sec^2 u)\). Applying this derivative to our problem, we have \(\sec^2(F(2x))\).
04
Differentiate the inner function
Now we differentiate the inner function, \(F(2x)\). The derivative of \(F(x)\) with respect to \(x\) is \(F'(x)\). Since we have \(F(2x)\), we need to apply the chain rule again, giving us \(F'(2x) \cdot 2\).
05
Combine the derivatives
Combining both the derivatives from steps 3 and 4, according to the chain rule, the derivative \(D_x an F(2x)\) is \(\sec^2(F(2x)) \cdot F'(2x) \cdot 2\).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with Vaia!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Chain Rule
The chain rule is an essential tool in calculus for finding the derivative of composite functions. It allows us to differentiate a function that is nested within another function.
When we consider a function of the form \(u(v(x))\), the chain rule helps break it down into the derivatives of the outer function \(u\) and the inner function \(v\).
The formula for the chain rule is straightforward:
When we consider a function of the form \(u(v(x))\), the chain rule helps break it down into the derivatives of the outer function \(u\) and the inner function \(v\).
The formula for the chain rule is straightforward:
- Take the derivative of the outer function \(u\), with respect to the inner function \(v(x)\), given as \(u'(v(x))\).
- Then, multiply it by the derivative of the inner function \(v(x)\), which is \(v'(x)\).
Composite Functions
Composite functions are essentially functions within functions. They enable us to build more complex operations by plugging one function into another.
This nesting structure is represented as \(f(g(x))\), where \(g(x)\) is the inner function and \(f\) is the outer function.
A composite function requires special handling when differentiating, often through the use of the chain rule.
Let's take the example given in the problem statement:
This nesting structure is represented as \(f(g(x))\), where \(g(x)\) is the inner function and \(f\) is the outer function.
A composite function requires special handling when differentiating, often through the use of the chain rule.
Let's take the example given in the problem statement:
- The component functions here are the tangent function (the outer function) and \(F(2x)\) (the inner function).
- The presence of an additional modification within \(F(2x)\), specifically, multiplying \(x\) by 2 makes the inner function slightly more complex.
Trigonometric Functions
Trigonometric functions like \(\sin, \cos,\) and \(\tan\) play a vital role in calculus. In differentiation, each of these functions has a specific derivative:
For \(\tan F(2x)\), applying the chain rule gives us \(\sec^2(F(2x))\) as the derivative of the outer function. This reveals the subtleties of dealing with trigonometric layers in composite scenarios.
- The derivative of \(\sin x\) is \(\cos x\).
- The derivative of \(\cos x\) is \(-\sin x\).
- The derivative of \(\tan x\) is \(\sec^2 x\).
For \(\tan F(2x)\), applying the chain rule gives us \(\sec^2(F(2x))\) as the derivative of the outer function. This reveals the subtleties of dealing with trigonometric layers in composite scenarios.
Derivatives
Derivatives are a core concept in calculus. They measure how a function changes as its input changes. Differentiation systematically finds the rate of change between variables.
Key points to keep in mind regarding derivatives include:
All these concepts combine to smoothly solve complex differentiation tasks, like finding \(D_x \, \tan F(2x)\). This results in a product of effective derivative strategies.
Key points to keep in mind regarding derivatives include:
- The derivative of a constant is zero. This reflects the idea that constants do not change.
- Basic differentiation rules (e.g., power rule, product rule) help handle various function types.
- Application of derivatives can involve compound rules like the chain rule when dealing with more intricate or layered functions.
All these concepts combine to smoothly solve complex differentiation tasks, like finding \(D_x \, \tan F(2x)\). This results in a product of effective derivative strategies.