Chapter 3: Problem 17
$$ \text { } \text { find } D_{x} y . $$ $$ y=\tan ^{2} x $$
Short Answer
Expert verified
The derivative is \( D_x y = 2 \tan x \cdot \sec^2 x \).
Step by step solution
01
Recognize the Function Form
The function given to us is \( y = \tan^2 x \). This can be rewritten using exponent rules as \( y = (\tan x)^2 \). The expression is a composite function where the outer function is \( u^2 \) with \( u = \tan x \).
02
Apply the Chain Rule
To differentiate \( y = (\tan x)^2 \), we will use the chain rule. The chain rule states that if \( y = f(g(x)) \), then \( \frac{dy}{dx} = f'(g(x)) \cdot g'(x) \).
03
Differentiate the Outer Function
Let's first differentiate the outer function. If \( u = \tan x \), then the outer function is \( u^2 \). The derivative of \( u^2 \) with respect to \( u \) is \( 2u \).
04
Differentiate the Inner Function
Now, differentiate the inner function \( u = \tan x \) with respect to \( x \). The derivative of \( \tan x \) is \( \sec^2 x \).
05
Apply the Chain Rule Derivatives
Now apply the chain rule: \( \frac{dy}{dx} = 2u \cdot \frac{du}{dx} \). Substitute in the values: \( \frac{dy}{dx} = 2(\tan x) \cdot \sec^2 x \).
06
Simplify the Expression
Finally, simplify the expression: \( D_x y = 2 \tan x \cdot \sec^2 x \). This is the derivative of \( y \) with respect to \( x \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Chain Rule
The chain rule is a fundamental technique in calculus for differentiating composite functions. It helps us find derivatives of functions that are composed of two or more functions. In our example, we have the function \( y = (\tan x)^2 \). This is a composite function because it contains the inner function \( \tan x \) nested within the outer function \( u^2 \).
The chain rule states: if you have a function \( y = f(g(x)) \), then the derivative is given by \( \frac{dy}{dx} = f'(g(x)) \cdot g'(x) \).
Applying this rule to our problem, we recognize:
The chain rule states: if you have a function \( y = f(g(x)) \), then the derivative is given by \( \frac{dy}{dx} = f'(g(x)) \cdot g'(x) \).
Applying this rule to our problem, we recognize:
- The outer function is \( u^2 \) with \( u = \tan x \).
- The inner function is \( u = \tan x \).
Trigonometric Functions
Trigonometric functions play a key role in calculus and are at the heart of this exercise. The basic trigonometric functions include sine, cosine, and tangent. Each of these functions has its own derivative, which is crucial for solving calculus problems where these functions are involved.
Tangent, or \( \tan x \), is particularly important here. It is the ratio of sine and cosine, \( \tan x = \frac{\sin x}{\cos x} \). Its derivative, \( \sec^2 x \), is derived from the chain rule applied to the trigonometric identity \( \frac{d}{dx} \left( \tan x \right) \).
Understanding the derivatives of trigonometric functions helps in accurately determining the slope of curves that are defined by trigonometric expressions. In our exercise, the derivative of \( \tan x \) is essential for applying the chain rule accurately.
Tangent, or \( \tan x \), is particularly important here. It is the ratio of sine and cosine, \( \tan x = \frac{\sin x}{\cos x} \). Its derivative, \( \sec^2 x \), is derived from the chain rule applied to the trigonometric identity \( \frac{d}{dx} \left( \tan x \right) \).
Understanding the derivatives of trigonometric functions helps in accurately determining the slope of curves that are defined by trigonometric expressions. In our exercise, the derivative of \( \tan x \) is essential for applying the chain rule accurately.
Derivative of Tangent
Finding the derivative of the tangent function is a vital step in this problem. Tangent, \( \tan x \), is a primary trigonometric function. The derivative of \( \tan x \) is \( \sec^2 x \).
This derivative can be understood by considering the fact that \( \tan x = \frac{\sin x}{\cos x} \). By using the quotient rule or known derivative rules, one can derive that its slope, or instantaneous rate of change, is described by \( \sec^2 x \).
Knowing the derivative of the tangent function allows you to solve more complex differential problems where tangent is part of a larger expression. For this exercise, it allows for the correct application of the chain rule when differentiating \( y = (\tan x)^2 \).
This derivative can be understood by considering the fact that \( \tan x = \frac{\sin x}{\cos x} \). By using the quotient rule or known derivative rules, one can derive that its slope, or instantaneous rate of change, is described by \( \sec^2 x \).
Knowing the derivative of the tangent function allows you to solve more complex differential problems where tangent is part of a larger expression. For this exercise, it allows for the correct application of the chain rule when differentiating \( y = (\tan x)^2 \).
Composite Functions
Composite functions involve one function nested inside another. The function \( y = (\tan x)^2 \) is an example where \( \tan x \) is the inner function and \( u^2 \) is the outer function. Calculus often requires finding the derivative of such composite expressions.
To differentiate a composite function, we break it down into its constituent parts. The derivative process involves:
To differentiate a composite function, we break it down into its constituent parts. The derivative process involves:
- Identifying the inner and outer functions.
- Using the chain rule to differentiate each part separately.
- Combining these derivatives to form the overall derivative of the composite function.