Least Squares Given \(n\) points \(\left(x_{1}, y_{1}\right),\left(x_{2},
y_{2}\right), \ldots\), \(\left(x_{n}, y_{n}\right)\) in the \(x y\) -plane, we
wish to find the line \(y=m x+b\) such that the sum of the squares of the
vertical distances from the points to the line is a minimum; that is, we wish
to minimize
$$
f(m, b)=\sum_{i=1}^{n}\left(y_{i}-m x_{i}-b\right)^{2}
$$
(a) Find \(\partial f / \partial m\) and \(\partial f / \partial b\), and set
these results equal to zero. Show that this leads to the system of equations
$$
\begin{aligned}
m \sum_{i=1}^{n} x_{i}^{2}+b \sum_{i=1}^{n} x_{i} &=\sum_{i=1}^{n} x_{i} y_{i}
\\\
m \sum_{i=1}^{n} x_{i}+n b &=\sum_{i=1}^{n} y_{i}
\end{aligned}
$$
(b) Solve this system for \(m\) and \(b\).
(c) Use the Second Partials Test (Theorem C) to show that \(f\) is minimized for
this choice of \(m\) and \(b\).