Chapter 12: Problem 10
Find the indicated limit or state that it does not exist. \(\lim _{(x, y) \rightarrow(0,0)} \frac{x^{4}-y^{4}}{x^{2}+y^{2}}\)
Short Answer
Expert verified
The limit is 0.
Step by step solution
01
Identify the Limit Type
The given limit is \( \lim_{(x, y) \to (0,0)} \frac{x^{4} - y^{4}}{x^{2} + y^{2}} \). This is a multivariable limit since it involves two variables: \(x\) and \(y\).
02
Substitute Directly to Check Undefined Form
Direct substitution of \(x=0\) and \(y=0\) into the given function results in the form \(\frac{0 - 0}{0 + 0} = \frac{0}{0}\), which is undefined. This suggests that further investigation is needed to evaluate the limit.
03
Examine Using Polar Coordinates
Convert to polar coordinates where \(x = r\cos(\theta)\) and \(y = r\sin(\theta)\). The expression becomes \(\frac{(r^4)(\cos^4(\theta) - \sin^4(\theta))}{r^2}= r^2(\cos^4(\theta) - \sin^4(\theta))\)
04
Evaluate the Modified Limit
The expression reduces to \(r^2(\cos^4(\theta) - \sin^4(\theta))\). As \(r \to 0\), regardless of \(\theta\), the expression approaches zero \((r^2 \cdot \, \text{some bounded function}) \to 0\cdot\text{constant} = 0\).
05
Use Path Approach for Verification
Check by approaching \( (0,0) \) along different paths. For example, using the path \(y=x\), the expression simplifies to \(\frac{x^4 - x^4}{x^2 + x^2} = 0\); using \(y=0\), it simplifies to \(\frac{x^4}{x^2} = x^2\) which goes to 0 as \(x\to 0\). All tested paths yield the same result, confirming the limit.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Polar Coordinates in Limits
When evaluating multivariable limits, such as the problem involving \( \lim_{(x, y) \to (0,0)} \frac{x^{4} - y^{4}}{x^{2} + y^{2}} \), polar coordinates can be a powerful tool. This approach transforms \(x\) and \(y\) into terms of \(r\) and \(\theta\), using the substitutions \(x = r\cos(\theta)\) and \(y = r\sin(\theta)\).
This substitution can simplify the evaluation of limits where direct substitution yields an undefined form.
This substitution can simplify the evaluation of limits where direct substitution yields an undefined form.
- With our example, substituting polar expressions, the original function becomes \(\frac{(r^4)(\cos^4(\theta) - \sin^4(\theta))}{r^2}= r^2(\cos^4(\theta) - \sin^4(\theta))\).
- As \(r \rightarrow 0\), \(r^2\) also approaches 0, effectively governing the limit's behavior to make it approach zero for any \(\theta\).
Undefined Forms in Calculus
An expression that results in \(\frac{0}{0}\) is known as an undefined form, a common scenario in calculus limit problems.
These forms suggest that simple substitutions aren't enough to find a limit, urging the need for alternative strategies.
These forms suggest that simple substitutions aren't enough to find a limit, urging the need for alternative strategies.
- In this particular limit exercise, substituting \(x=0\) and \(y=0\) results in \(\frac{0 - 0}{0 + 0} = \frac{0}{0}\).
- This signals that further analysis is necessary because the result is undefined, meaning the limit could exist, not exist, or equal different values depending on the path taken.
Path Approach in Calculus
The path approach is a method to evaluate limits by examining the function along various trajectories that lead to the same point. This approach helps determine if a multivariable limit exists or varies by path.
By assessing different specific paths to approach \((0,0)\), additional insights into the function are obtained:
By assessing different specific paths to approach \((0,0)\), additional insights into the function are obtained:
- For the given scenario, one such path is \(y=x\), leading to \(\frac{x^4 - x^4}{x^2 + x^2} = 0\).
- Another path is \(y=0\), which simplifies to \(\frac{x^4}{x^2} = x^2\), also reaching 0 as \(x\to 0\).