Chapter 11: Problem 15
Find the parametric equations of the line through \((5,-3,4)\) that intersects the \(z\) -axis at a right angle.
Short Answer
Expert verified
Parametric equations: \(x = 5 + at, y = -3 + bt, z = 4\).
Step by step solution
01
Understand the Problem
We need to find parametric equations for a line that passes through the point \((5, -3, 4)\) and intersects the z-axis at a right angle.
02
Determine the Direction Vector
A line perpendicular to the z-axis will have a direction vector of the form \((a, b, 0)\) because the line must be parallel to the xy-plane.
03
Write the Parametric Equations
The parametric equations for a line through the point \((5, -3, 4)\) with direction vector \((a, b, 0)\) will be:\[x = 5 + at,\quad y = -3 + bt,\quad z = 4\]
04
Ensure Z-Axis Perpendicularity
Since the line must intersect the z-axis perpendicularly, the z-component of the direction vector is 0, which is already satisfied with direction vector \((a, b, 0)\).
05
Solution Verification
The line intersects the z-axis when \(x = 0\) and \(y = 0\), since we need the line to pass through the z-axis. However, it is sufficient that the direction vector only affects x and y to ensure perpendicularity to the z-axis, as z remains constant. Thus, our set of equations is valid.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with Vaia!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Perpendicular Lines
When discussing lines in three-dimensional space, two lines are perpendicular if they meet at a right angle. A line that is perpendicular to the z-axis specifically has to lie entirely within a plane parallel to the xy-plane. This is because the z-axis is vertical, so any line that crosses it perpendicularly does so without moving up or down the z-values. The essence of ensuring a perpendicular intersection with the z-axis involves understanding that the only varying components of the line's direction would be along the x and y axes, leaving the z component fixed.
Direction Vector
The direction vector of a line is crucial as it defines the line's pathway through space. In our problem, we determined our direction vector to have the form \((a, b, 0)\). This choice results because a direction vector \((a, b, 0)\) ensures that the line runs parallel to the xy-plane and thus remains perpendicular to the z-axis.
- The x and y components \(a\) and \(b\) allow the line to move through different x and y coordinates.
- The z component being zero ensures perpendicularity, as there is no z direction displacement.
Z-Axis Intersection
For the line to intersect the z-axis, we usually think of it crossing the plane where the x and y coordinates are zero. However, for our specific problem, this constraint doesn't necessarily apply strictly; rather, we need the line's orientation to remain consistently aligned so it touches the z-axis at one fixed point along that axis. Consequently, the variation in x and y as defined by the parametric equations allows for looking at how these interact rather than directly demanding \(x = 0\) and \(y = 0\).
- The critical focus is on how the line's z value remains constant, thereby automatically ensuring an intersection with the z-axis at one point along its line.
- The direction is exclusively along the x and y path, which effectively addresses where the line covers as \(t\) changes.
Parametric Form in 3D
Parametric equations in 3D define a line using separate expressions for each coordinate as a function of a common parameter. Here, we use \(t\), with equations:
- \(x = 5 + at\)
- \(y = -3 + bt\)
- \(z = 4\)
- The starting point of the line is \((5, -3, 4)\), and \(t = 0\) will plug directly into this origin.
- As \(t\) shifts, it records how far we've moved from this initial point, controlled by our chosen direction vector.
- The equations provide the line's representation in clear numerical terms that describe both location and direction in 3D space.