The magnitude of a vector is one of its key characteristics and reflects the vector's length. Mathematically, for a vector \( \mathbf{a} = \langle a_1, a_2 \rangle \), its magnitude \( \|\mathbf{a}\| \) is calculated using the formula:
\( \|\mathbf{a}\| = \sqrt{a_1^2 + a_2^2} \)
This measure is important in calculating the strength and impact in various fields such as physics. Let's calculate the magnitudes of the exercise vectors:
For \( \mathbf{u} = \langle 0,0 \rangle \), the magnitude is \( \|\mathbf{u}\| = \sqrt{0^2 + 0^2} = 0 \).
Now the vector \( \mathbf{v} = \langle -3,4 \rangle \):
The magnitude is \( \|\mathbf{v}\| = \sqrt{(-3)^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5 \).
These magnitudes tell us that \( \mathbf{v} \) has a substantial length of 5 units, while \( \mathbf{u} \) is essentially a point.