Chapter 1: Problem 71
Show that \(a \neq 0 \Rightarrow a^{2}+1 / a^{2} \geq 2\). Hint: Consider \((a-1 / a)^{2}\)
Short Answer
Expert verified
If \(a \neq 0\), then \(a^2 + \frac{1}{a^2} \geq 2\).
Step by step solution
01
Expand the Given Expression
Consider the expression \[ (a - \frac{1}{a})^2. \]Expanding this expression using the distributive property gives:\[ a^2 - 2 \cdot a \cdot \frac{1}{a} + \left(\frac{1}{a}\right)^2 = a^2 - 2 + \frac{1}{a^2}. \]
02
Use Non-negativity of Squares
Since \[ (a - \frac{1}{a})^2 \geq 0, \]we know that the expression \[ a^2 - 2 + \frac{1}{a^2} \geq 0. \]
03
Re-arrange to the Desired Form
Rearranging the inequality \[ a^2 - 2 + \frac{1}{a^2} \geq 0, \]we add 2 to both sides to get:\[ a^2 + \frac{1}{a^2} \geq 2. \]
04
Conclusion
We have shown that if \(a eq 0\), then\[ a^2 + \frac{1}{a^2} \geq 2. \]This completes the proof using the square of the difference \((a - \frac{1}{a})^2\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Expressions
A quadratic expression is any mathematical statement that includes a term with the variable raised to the second power. The general form is usually written as \(ax^2 + bx + c\), where \(a\), \(b\), and \(c\) are constants. Quadratic expressions can appear in numerous forms when solving complex problems.
In the given exercise, we deal with expressions like \(a^2\) and \(\frac{1}{a^2}\), which match the characteristics of quadratic expressions. Understanding these allows us to manipulate and solve inequalities involving them.
In the given exercise, we deal with expressions like \(a^2\) and \(\frac{1}{a^2}\), which match the characteristics of quadratic expressions. Understanding these allows us to manipulate and solve inequalities involving them.
- Watch for the second-degree term, as it dictates the quadratic nature of the expression.
- Recognizing the structure helps in expanding and simplifying expressions correctly.
Expanding Expressions
Expanding expressions involves rewriting a product or a power in an expanded form. This technique is especially useful when dealing with expressions that involve factoring, squaring, or multiplying binomials.
In the exercise, we expanded \((a - \frac{1}{a})^2\) to transform it into a more familiar form:
In the exercise, we expanded \((a - \frac{1}{a})^2\) to transform it into a more familiar form:
- Apply the distributive property: it's essential when expanding expressions like \((a - \frac{1}{a})^2 = a^2 - 2\cdot a\cdot \frac{1}{a} + \left(\frac{1}{a}\right)^2\).
Non-negativity
Non-negativity is a critical concept when dealing with inequalities. A non-negative expression is one that is greater than or equal to zero.
In this problem, we used the non-negativity of \((a - \frac{1}{a})^2\), which means it is always \(\geq 0\). This property is fundamental, and understanding it can help us rearrange inequalities and deduce useful relationships.
In this problem, we used the non-negativity of \((a - \frac{1}{a})^2\), which means it is always \(\geq 0\). This property is fundamental, and understanding it can help us rearrange inequalities and deduce useful relationships.
- Remember: the square of any real number is always non-negative.
- Use this property to establish boundaries or constraints within inequalities; it often leads directly to the solution.
Mathematical Proofs
Mathematical proofs demonstrate the truth of a statement using a systematic series of logical steps. Proofs rely heavily on logical reasoning, known mathematical principles, and properties.
In the exercise, we used the expansion and non-negativity to craft a proof that \(a^2 + \frac{1}{a^2} \geq 2\). Reflect on the following:
In the exercise, we used the expansion and non-negativity to craft a proof that \(a^2 + \frac{1}{a^2} \geq 2\). Reflect on the following:
- Each step logically follows from the previous one, ensuring that our conclusion is sound.
- Proofs vary in complexity but always aim to bridge given or known information with a new, often insightful result.