Chapter 1: Problem 18
, plot the graph of each equation. Begin by checking for symmetries and be sure to find all \(x\) - and \(y\) -intercepts.. $$ x^{4}+y^{4}=1 $$
Short Answer
Expert verified
The graph is a symmetric curve called a Lemniscate, with intercepts at (1,0), (-1,0), (0,1), and (0,-1).
Step by step solution
01
Check for Symmetry
To check for symmetry, substitute 1. - Replace \(x\) with \(-x\)\. Since the equation \(x^{4} + y^{4} = 1\) becomes \((-x)^{4} + y^{4} = 1\), which is the same after substitution, it is symmetric about the \text{y-axis}\. - Replace \(y\) with \(-y\)\. The equation \(x^{4} + (-y)^{4} = 1\) remains unchanged, so it is symmetric about the \text{x-axis}\. - Replace \(x\) with \(-x\)\ and \(y\) with \(-y\)\. The equation \((-x)^{4} + (-y)^{4} = 1\) is still the same. Therefore, it is symmetric about the \text{origin}\.
02
Find x-intercepts
To find the x-intercepts, set \(y = 0\) in the equation \(x^{4} + y^{4} = 1\):\[ x^{4} + 0^{4} = 1 \Rightarrow x^{4} = 1\]Solving for \(x\),\[ x = \pm 1.\]Thus, the x-intercepts are \((1, 0)\) and \((-1, 0)\).
03
Find y-intercepts
To find the y-intercepts, set \(x = 0\) in the equation \(x^{4} + y^{4} = 1\):\[ 0^{4} + y^{4} = 1 \Rightarrow y^{4} = 1\]Solving for \(y\),\[ y = \pm 1.\]Thus, the y-intercepts are \((0, 1)\) and \((0, -1)\).
04
Plot the Curve
The equation \(x^{4} + y^{4} = 1\) represents a figure known as a \text{Lemniscate}\. Since the equation is symmetric about both the axes and the origin, it will be symmetric in all quadrants. The points we found, \((1,0), (-1,0), (0,1), (0,-1)\) and the symmetry suggest that the curve looks like a stretched circle in the shape of a \text{diamond}\, but with rounded corners at those points. Plot these points and draw a smooth curve through these to graph the equation.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Symmetry in Graphs
In mathematics, understanding the symmetry of a graph can make analyzing and sketching it much easier. Symmetry implies that one part of the graph mirrors another, providing a neat and predictable structure to work with.
To determine symmetry, one can perform simple substitutions in the given equation.
To determine symmetry, one can perform simple substitutions in the given equation.
- To check for y-axis symmetry, replace every occurrence of \(x\) with \(-x\). If the equation remains unchanged, it is symmetric about the y-axis.
- For x-axis symmetry, substitute \(y\) with \(-y\). If the equation holds, it's symmetric about the x-axis.
- To see if the graph is symmetric about the origin, replace both \(x\) with \(-x\) and \(y\) with \(-y\). If the equation remains the same, it has origin symmetry.
X-intercepts and Y-intercepts
Finding x-intercepts and y-intercepts is a crucial step in graphing. These intercepts are points where the graph crosses the x-axis or y-axis.
- **X-intercepts:** To find these, we set \(y = 0\) in the equation and solve for \(x\). In the equation \(x^4 + y^4 = 1\), substituting \(y = 0\) gives \(x^4 = 1\). Solving this, we find \(x = \pm 1\). Hence, the x-intercepts are \((1, 0)\) and \((-1, 0)\).
- **Y-intercepts:** Here, set \(x = 0\) and solve for \(y\). Again, using \(x^4 + y^4 = 1\), we get \(y^4 = 1\), leading to \(y = \pm 1\). Thus, the y-intercepts are \((0, 1)\) and \((0, -1)\).
These intercepts serve as reference points when plotting and give insight into the overall behavior of the graph near the axes.
- **X-intercepts:** To find these, we set \(y = 0\) in the equation and solve for \(x\). In the equation \(x^4 + y^4 = 1\), substituting \(y = 0\) gives \(x^4 = 1\). Solving this, we find \(x = \pm 1\). Hence, the x-intercepts are \((1, 0)\) and \((-1, 0)\).
- **Y-intercepts:** Here, set \(x = 0\) and solve for \(y\). Again, using \(x^4 + y^4 = 1\), we get \(y^4 = 1\), leading to \(y = \pm 1\). Thus, the y-intercepts are \((0, 1)\) and \((0, -1)\).
These intercepts serve as reference points when plotting and give insight into the overall behavior of the graph near the axes.
Even Function
In calculus, an even function is a function that satisfies a specific symmetry property. For a function \(f(x)\), it is considered even if \(f(-x) = f(x)\) for every \(x\) in its domain.
This property means that the graph of an even function is symmetric with respect to the y-axis. Essentially, the left and right sides of the graph mirror each other.
This property means that the graph of an even function is symmetric with respect to the y-axis. Essentially, the left and right sides of the graph mirror each other.
- In the equation \(x^4 + y^4 = 1\), each polynomial term \(x^4\) and \(y^4\) contributes to the evenness, as raising a negative number to an even power results in a positive number.
- This characteristic aligns with the symmetry tests for the graph, corroborating that it remains unchanged when \(x\) or \(y\) are negated.
Lemniscate
The term "Lemniscate" refers to a specific type of curve that looks like a figure-eight or infinity symbol. It is a classic shape in mathematics, known for its symmetrical properties.
In the context of the equation \(x^4 + y^4 = 1\), the graph is a lemniscate but with a twist.
In the context of the equation \(x^4 + y^4 = 1\), the graph is a lemniscate but with a twist.
- The curve appears like a diamond with rounded points, ensuring smooth transitions between the axes and intercepts.
- This type of lemniscate is a result of the high symmetry the equation possesses, being symmetric around both axes and the origin.