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43-48 Find the limit, if it exists. If the limit does not exist, explain why.

47. \(\mathop {{\bf{lim}}}\limits_{x \to {{\bf{0}}^ + }} \left( {\frac{{\bf{1}}}{x} - \frac{{\bf{1}}}{{\left| x \right|}}} \right)\)

Short Answer

Expert verified

Limit does not exist.

Step by step solution

01

Simplify the expression given in the limit

If \(x < 0\), then \(\left| x \right| = - x\).

The expression in the limit can be written as,

\(\begin{array}{c}\mathop {\lim }\limits_{x \to {0^ - }} \left( {\frac{1}{x} - \frac{1}{{\left| x \right|}}} \right) &=& \mathop {\lim }\limits_{x \to {0^ - }} \left( {\frac{1}{x} - \left( { - \frac{1}{x}} \right)} \right)\\ &=& \mathop {\lim }\limits_{x \to {0^ - }} \left( {\frac{2}{x}} \right)\end{array}\)

02

Find the value of the limit

For the expression \(\mathop {\lim }\limits_{x \to {0^ - }} \left( {\frac{2}{x}} \right)\), as \(x \to 0\)the term \(\frac{2}{x}\) is not defined.

So, the limit does not exist.

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Most popular questions from this chapter

Explain in your own words what is meant by the equation

\(\mathop {{\bf{lim}}}\limits_{x \to {\bf{2}}} f\left( x \right) = {\bf{5}}\)

Is it possible for this statement to be true and yet \(f\left( {\bf{2}} \right) = {\bf{3}}\)? Explain.

43-45 Find the numbers at which f is discontinuous. At which of these numbers is f continuous from the right, from the left, or neither? Sketch the graph of f?

45. \(f\left( x \right) = \left\{ {\begin{array}{*{20}{c}}{x + {\bf{2}}}&{{\bf{if}}\,\,\,x < {\bf{0}}}\\{{e^x}}&{{\bf{if}}\,\,\,{\bf{0}} \le x \le {\bf{1}}}\\{{\bf{2}} - x}&{{\bf{if}}\,\,\,x > {\bf{1}}}\end{array}} \right.\)

Sketch the graph of the function gthat is continuous on its domain \(\left( { - {\bf{5}},{\bf{5}}} \right)\) and where\(g\left( {\bf{0}} \right) = {\bf{1}}\), \(g'\left( {\bf{0}} \right) = {\bf{1}}\), \(g'\left( { - {\bf{2}}} \right) = {\bf{0}}\), \(\mathop {{\bf{lim}}}\limits_{x \to - {{\bf{5}}^ + }} g\left( x \right) = \infty \), and \(\mathop {{\bf{lim}}}\limits_{x \to - {{\bf{5}}^ - }} g\left( x \right) = {\bf{3}}\).

Show by implicit differentiation that the tangent to the ellipse \(\frac{{{x^{\rm{2}}}}}{{{a^{\rm{2}}}}} + \frac{{{y^{\rm{2}}}}}{{{b^{\rm{2}}}}} = {\rm{1}}\) at the point \(\left( {{x_{\rm{0}}},{y_{\rm{0}}}} \right)\)is \(\frac{{{x_{\rm{0}}}x}}{{{a^{\rm{2}}}}} + \frac{{{y_{\rm{0}}}y}}{{{b^{\rm{2}}}}} = {\rm{1}}\).

If \(f\left( x \right) = 3{x^2} - {x^3}\), find \(f'\left( 1 \right)\) and use it to find an equation of the tangent line to the curve \(y = 3{x^2} - {x^3}\) at the point \(\left( {1,2} \right)\).

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