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Each limit represents the derivative of some function f at some number a. State such as an f and a in each case.

\(\mathop {{\bf{lim}}}\limits_{x \to \frac{{\bf{1}}}{{\bf{4}}}} \frac{{\frac{{\bf{1}}}{x} - {\bf{4}}}}{{x - \frac{{\bf{1}}}{{\bf{4}}}}}\)

Short Answer

Expert verified

The function is \(f\left( x \right) = \frac{1}{x}\) and \(a = \frac{1}{4}\).

Step by step solution

01

Step 1:Write the given limit as in Definition 4

According to definition 5, the derivative of a function f is given by the equation:

\(f'\left( a \right) = \mathop {\lim }\limits_{x \to a} \frac{{f\left( x \right) - f\left( a \right)}}{{x - a}}\)

The expression \(\mathop {\lim }\limits_{x \to \frac{1}{4}} \frac{{\frac{1}{x} - 4}}{{x - \frac{1}{4}}}\) can be written as:

\(\mathop {\lim }\limits_{x \to \frac{1}{4}} \frac{{\frac{1}{x} - 4}}{{x - \frac{1}{4}}} = \mathop {\lim }\limits_{x \to \frac{1}{4}} \frac{{\frac{1}{x} - \frac{1}{{\left( {1/4} \right)}}}}{{x - \frac{1}{4}}}\)

02

Find the value of a and function f

By the limit\(\mathop {\lim }\limits_{x \to \frac{1}{4}} \frac{{\frac{1}{x} - 4}}{{x - \frac{1}{4}}} = \mathop {\lim }\limits_{x \to \frac{1}{4}} \frac{{\frac{1}{x} - \frac{1}{{\left( {1/4} \right)}}}}{{x - \frac{1}{4}}}\), the value of a is \(\frac{1}{4}\).

The functionf can be expressed as:

\(f\left( x \right) = \frac{1}{x}\)

Thus, the function is \(f\left( x \right) = \frac{1}{x}\), and the value of a is \(\frac{1}{4}\).

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Most popular questions from this chapter

The point \(P\left( {{\bf{0}}.{\bf{5}},{\bf{0}}} \right)\) lies on the curve \(y = {\bf{cos}}\pi x\).

(a) If Q is the point \(\left( {x,{\bf{cos}}\pi x} \right)\), find the slope of the secant line PQ (correct to six decimal places) for the following values of x:

(i) 0 (ii) 0.4 (iii) 0.49 (iv) 0.499 (v) 1 (vi) 0.6 (vii) 0.51 (viii) 0.501

(b) Using the results of part (a), guess the value of the slope of tangent line to the curve at \(P\left( {{\bf{0}}.{\bf{5}},{\bf{0}}} \right)\).

(c) Using the slope from part (b), find an equation of the tangent line to the curve at \(P\left( {{\bf{0}}.{\bf{5}},{\bf{0}}} \right)\).

(d) Sketch the curve, two of the secant lines, and the tangent line.

The cost (in dollars) of producing \[x\] units of a certain commodity is \(C\left( x \right) = 5000 + 10x + 0.05{x^2}\).

(a) Find the average rate of change of \(C\) with respect to \[x\]when the production level is changed

(i) From \(x = 100\)to \(x = 105\)

(ii) From \(x = 100\)to \(x = 101\)

(b) Find the instantaneous rate of change of \(C\) with respect to\(x\) when \(x = 100\). (This is called the marginal cost. Its significance will be explained in Section 3.7.)

19-32: Prove the statement using the \(\varepsilon ,\delta \) definition of a limit.

30. \(\mathop {\lim }\limits_{x \to 2} \left( {{x^2} + 2x - 7} \right) = 1\)

If \(g\left( x \right) = {x^4} - 2\), find \(g'\left( 1 \right)\) and use it to find an equation of the tangent line to the curve \(y = {x^4} - 2\) at the point \(\left( {1, - 1} \right)\).

41-42 Show that f is continuous on \(\left( { - \infty ,\infty } \right)\).

\(f\left( x \right) = \left\{ {\begin{array}{*{20}{c}}{{\bf{1}} - {x^{\bf{2}}}}&{{\bf{if}}\,\,x \le {\bf{1}}}\\{{\bf{ln}}\,x}&{{\bf{if}}\,\,\,x > {\bf{1}}}\end{array}} \right.\)

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