Chapter 2: Q40E (page 77)
39-40 Locate the discontinuities of the function and illustrate by graphing.
\(y = {\bf{arctan}}\frac{{\bf{1}}}{x}\)
Short Answer
The function is discontinuous at \(x = 0\).
Chapter 2: Q40E (page 77)
39-40 Locate the discontinuities of the function and illustrate by graphing.
\(y = {\bf{arctan}}\frac{{\bf{1}}}{x}\)
The function is discontinuous at \(x = 0\).
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Get started for freeEach limit represents the derivative of some function f at some number a. State such as an f and a in each case.
\(\mathop {{\bf{lim}}}\limits_{h \to {\bf{0}}} \frac{{{\bf{tan}}\left( {\frac{\pi }{{\bf{4}}} + h} \right) - {\bf{1}}}}{h}\)
Calculate each of the limits
Find equations of both the tangent lines to the ellipse\({{\rm{x}}^{\rm{2}}}{\rm{ + 4}}{{\rm{y}}^{\rm{2}}}{\rm{ = 36}}\)that pass through the point \(\left( {{\rm{12,3}}} \right)\)
To prove that sine is continuous, we need to show that \(\mathop {\lim }\limits_{x \to a} \sin x = \sin a\) for every number a. By Exercise 65 an equivalent statement is that
\(\mathop {\lim }\limits_{h \to 0} \sin \left( {a + h} \right) = \sin a\)
Use (6) to show that this is true.
\({x^{\rm{2}}} + {y^{\rm{2}}} = {r^{\rm{2}}}\), \(ax + by = {\rm{0}}\).
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