Let \(f\left( x \right) = {x^x}\).
Evaluate the function at \(t = 0.1\) as shown below:
\(\begin{aligned}\mathop {\lim }\limits_{x \to {{0.1}^ + }} {x^x} &= {\left( {0.1} \right)^{0.1}}\\ &= 0.794328\end{aligned}\)
The other values are obtained in a similar way listed in the table as shown below:
\(x\) | \(f\left( x \right)\) |
\(\begin{aligned}0.1\\0.01\\0.001\\0.0001\end{aligned}\) | \(\begin{aligned}0.794328\\0.954993\\0.993116\\0.999079\end{aligned}\) |
It is observed from the table that left, and right limits are the same and therefore, \(\mathop {\lim }\limits_{x \to {0^ + }} f\left( x \right) = 1\).
The procedure to draw the graph of the equation by using the graphing calculator is as follows:
To check the answer visually, draws the graph of the function\(f\left( x \right) = {x^x}\)by using the graphing calculator as shown below:
- Open the graphing calculator. Select the “STAT PLOT” and enter the equation\({X^X}\)in the\({Y_1}\)tab.
- Enter the “GRAPH” button in the graphing calculator.
Visualization of the graph of the function \(f\left( x \right) = {x^x}\)is shown below:

It is observed from the graph that the result of the limit is 1 is confirmed.
Thus, the value of the limit is \(\mathop {\lim }\limits_{x \to {0^ + }} f\left( x \right) = 1\).