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A rechargeable battery is plugged into a charger. The graph shows \(C\left( t \right)\), the percentage of full capacity that the battery reaches as a function of time \(t\) elapsed (in hours).

(a) What is the meaning of the derivative \(C'\left( t \right)\)?

(b) Sketch the graph of \(C'\left( t \right)\). What does the graph tell you?

Short Answer

Expert verified

(a) The derivative of \(C'\left( t \right)\) represents the instantaneous rate of change of full capacity over an elapsed time in hours.

(b) The graph is shown below:

The graph of \(C'\left( t \right)\) shows that the rate of change of percentage of full capacity is decreasing and reaching 0.

Step by step solution

01

Explain the derivative \(C'\left( t \right)\)

a) The derivative \(C'\left( t \right)\) represents the instantaneous rate of change of full capacity over an elapsed time in hours.

02

Sketch the graph of \(C'\left( t \right)\)

b) Consider some points \(A,B,C,\) and \(D,\) to plot on the graph of the given function \(C\left( t \right)\). We can estimate the graph of derivatives from these points.

Sketch the given graph of the function with the above points as shown below:

To determine the value of the derivative at any value of \(t\), we can draw the tangent at the point \(\left( {t,C\left( t \right)} \right)\) and estimate the slope.

The slope of the function \(C\left( t \right)\) is \(C'\left( A \right)\) can be determined as the ratio of the rise and run that appears to be equal. The function \(C\left( t \right)\) is increasing at \(x = A\)—the value of \(C'\left( A \right)\) is 40.

The function \(C\left( t \right)\) is increasing at \(x = B\). Hence, the value of \(C'\left( B \right)\) is 20.

It is observed that the tangent at \(t = C,D\) is horizontal. Therefore the slope is zero and it follows that the value of \(C'\left( C \right) = C'\left( D \right) = 0\).

It is observed that the tangent of four points has a positive slope, so \(C'\left( t \right)\) is positive.

Use the above point to estimate the derivative of the function as shown below:

03

Explain the graph of \(C'\)

The graph of \(C'\) shows that the rate of change of percentage of full capacity in decreasing and reaching to 0.

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Most popular questions from this chapter

(a) The curve with the equation \({y^2} = 5{x^4} - {x^2}\)is called akampyle of Eudoxus. Find and equation of the tangent line to this curve at the point\(\left( {1,2} \right)\)

(b) Illustrate part\(\left( a \right)\)by graphing the curve and the tangent line on a common screen. (If your graph device will graph implicitly defined curves, then use that capability. If not, you can still graph this curve by graphing its upper and lower halves separately.)

Find the points on the lemniscate in Exercise 23 where the tangent is horizontal.

The table shows the position of a motorcyclist after accelerating from rest.

t(seconds)

0

1

2

3

4

5

6

s(feet)

0

4.9

20.6

46.5

79.2

124.8

176.7

(a) Find the average velocity for each time period:

(i) \(\left( {{\bf{2}},{\bf{4}}} \right)\) (ii) \(\left( {{\bf{3}},{\bf{4}}} \right)\) (iii) \(\left( {{\bf{4}},{\bf{5}}} \right)\) (iv) \(\left( {{\bf{4}},{\bf{6}}} \right)\)

(b) Use the graph of s as a function of t to estimate the instantaneous velocity when \(t = {\bf{3}}\).

19-24Explain why the function is discontinuous at the given number\(a\). Sketch the graph of the function.

20. \(f\left( x \right) = \left\{ {\begin{array}{*{20}{c}}{\frac{1}{{x + 2}}}&{if\;x \ne 2}\\1&{if\;x = - 2}\end{array}} \right.\), \({\bf{a = - 2}}\)

The point \(P\left( {{\bf{0}}.{\bf{5}},{\bf{0}}} \right)\) lies on the curve \(y = {\bf{cos}}\pi x\).

(a) If Q is the point \(\left( {x,{\bf{cos}}\pi x} \right)\), find the slope of the secant line PQ (correct to six decimal places) for the following values of x:

(i) 0 (ii) 0.4 (iii) 0.49 (iv) 0.499 (v) 1 (vi) 0.6 (vii) 0.51 (viii) 0.501

(b) Using the results of part (a), guess the value of the slope of tangent line to the curve at \(P\left( {{\bf{0}}.{\bf{5}},{\bf{0}}} \right)\).

(c) Using the slope from part (b), find an equation of the tangent line to the curve at \(P\left( {{\bf{0}}.{\bf{5}},{\bf{0}}} \right)\).

(d) Sketch the curve, two of the secant lines, and the tangent line.

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