Chapter 1: Q7E (page 7)
The graph of \(y = \sqrt {{\bf{3}}x - {x^{\bf{2}}}} \) is given. Use transformations to create a function whose graph is as shown.
Short Answer
The new function is \(y = - \sqrt { - {x^2} - 5x - 4} - 1\).
Chapter 1: Q7E (page 7)
The graph of \(y = \sqrt {{\bf{3}}x - {x^{\bf{2}}}} \) is given. Use transformations to create a function whose graph is as shown.
The new function is \(y = - \sqrt { - {x^2} - 5x - 4} - 1\).
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Get started for free49-52 Evaluate \(f\left( { - 3} \right),f\left( 0 \right),\) and \(f\left( 2 \right)\) for the piecewise-defined function. Then sketch the graph of the function.
50. \(f\left( x \right) = \left\{ \begin{aligned}5\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\mathop{\rm if}\nolimits} \,\,x < 2\\\frac{1}{2}x - 3\,\,\,{\mathop{\rm if}\nolimits} \,\,x \ge 2\end{aligned} \right.\)
Determine whether f is even, odd, or neither. You may wish to use a graphing calculator or computer to check your answer visually.
82. \(f\left( x \right) = \frac{{{x^{\bf{2}}}}}{{{x^{\bf{4}}} + {\bf{1}}}}\)
The graph shows the power consumption for a day in September in San Francisco. (P is measured in megawatts; t is measured in hours starting at midnight.)
(a) What was the power consumptions at 6 AM? At 6 PM?
(b) When was the power consumption the lowest? When was it the highest? Do these times seem reasonable?
Temperature readings \(T\) (in \(^\circ F\) ) were recorded every two hours from midnight to 2:00 PM in Atlanta on a day in June. The time \(t\) was measured in hours from midnight.
\(t\) | 0 | 2 | 4 | 6 | 8 | 10 | 12 | 14 |
\(T\) | 74 | 69 | 68 | 66 | 70 | 78 | 82 | 86 |
(a) Use the readings to sketch a rough graph of T as a function of \(t\).
(b) Use your graph to estimate the temperature at 9:00 AM.
Evaluate \(f\left( { - {\bf{3}}} \right)\), \(f\left( {\bf{0}} \right)\), and \(f\left( {\bf{2}} \right)\) for the piecewise defined function. Then sketch the graph of the function.
\(f\left( x \right) = \left\{ {\begin{aligned}{ - {\bf{1}}}&{{\bf{if}}\;\;x \le {\bf{1}}}\\{{\bf{7}} - {\bf{2}}x}&{{\bf{if}}\;\;x > {\bf{1}}}\end{aligned}} \right.\)
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