Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Trees grow faster and form wider rings in warm years and grow more slowly and form narrower rings in cooler years. The figure shows the ring widths of a Siberian pine from 1500 to 2000.

(a) What is the range of the ring width function?

(b) What does the graph tend to say about the temperature of the earth? Does the graph reflect the volcanic eruptions of the mid-19th century?

Short Answer

Expert verified

a. The range of the ring width function is \(\left( {0,1.6} \right)\).

b. There was a variation in the mid-19th century, which could have been caused by volcanic eruptions.

Step by step solution

01

Determine the range of the ring width function

a)

The ring width varies from around \(0{\mathop{\rm mm}\nolimits} \) to about \(1.6{\mathop{\rm mm}\nolimits} \). Therefore, the range of the ring width function is about \(\left( {0,1.6} \right)\).

Thus, the range of the ring width function is \(\left( {0,1.6} \right)\).

02

Interpret what the graph says about the temperature of the earth

b)

The graph shows that the earth slowly cooled from the year 1550 to 1700, warmed into the late 1700s, cooled again in the late 1800s, and has been slowly warming since then.There was a variation in the mid-19th century, which could have been caused by volcanic eruptions.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Classify each function as a power function, root function, polynomial (state its degree), rational function, algebraic function, trigonometric function, exponential function, or logarithmic function.

(a) \(f\left( x \right) = {x^{\bf{3}}} + {\bf{3}}{x^{\bf{2}}}\)

(b) \(g\left( t \right) = co{s^{\bf{2}}}t - sint\)

(c) \(r\left( t \right) = {t^{\sqrt 3 }}\)

(d) \(v\left( t \right) = {{\bf{8}}^t}\)

(e) \(y = \frac{{\sqrt x }}{{{x^2} + 1}}\)

(f) \(g\left( u \right) = lo{g_{10}}u\)

39-46 find the domain of the function.

46. \(h\left( x \right) = \sqrt {{x^2} - 4x - 5} \)

Evaluate \(f\left( { - {\bf{3}}} \right)\), \(f\left( {\bf{0}} \right)\), and \(f\left( {\bf{2}} \right)\) for the piecewise defined function. Then sketch the graph of the function.

\(f\left( x \right) = \left\{ {\begin{aligned}{ - {\bf{1}}}&{{\bf{if}}\;\;x \le {\bf{1}}}\\{{\bf{7}} - {\bf{2}}x}&{{\bf{if}}\;\;x > {\bf{1}}}\end{aligned}} \right.\)

The point \(P\left( {{\bf{2}}, - {\bf{1}}} \right)\) lies on the curve \(y = \frac{{\bf{1}}}{{{\bf{1}} - x}}\).

(a) If Q is the point \(\left( {x,\frac{{\bf{1}}}{{{\bf{1}} - x}}} \right)\), find the slope of the secant line PQ (correct to six decimal places) for the following values of x:

(i) 1.5 (ii) 1.9 (iii) 1.99 (iv) 1.999 (v) 2.5 (vi) 2.1(vii) 2.01 (viii) 2.001

(b) Using the results of part (a), guess the value of the slope of tangent line to the curve at \(P\left( {{\bf{2}}, - {\bf{1}}} \right)\).

(c) Using the slope from part (b), find an equation of the tangent line to the curve at \(P\left( {{\bf{2}}, - {\bf{1}}} \right)\).

79-80 the graph of a function defined for \(x \ge 0\) is given. Complete the graph for \(x < 0\) to make (a) an even function and (b) an odd function.

80.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free