Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Make a rough sketch by hand of the graph of the function. Use the graphs given in Figures 3 and 15 and, if necessary, the transformations of Section 1.3.

10. \(h\left( x \right) = {\bf{2}}{\left( {\frac{{\bf{1}}}{{\bf{2}}}} \right)^x} - {\bf{3}}\)

Short Answer

Expert verified

The graph of the function \(h\left( x \right) = 2{\left( {\frac{1}{2}} \right)^x} - 3\) is obtained from the graph of \(h\left( x \right) = {\left( {\frac{1}{2}} \right)^x}\) after the following transformation:

  • Stretch the graph by a factor of 2.
  • Then, shift the graph 3 units downward.

Step by step solution

01

Write the transformation to find the graph of \(h\left( x \right) = {\bf{2}}{\left( {\frac{{\bf{1}}}{{\bf{2}}}} \right)^x} - {\bf{3}}\)

The graph of the function \(h\left( x \right) = 2{\left( {\frac{1}{2}} \right)^x} - 3\) is obtained from the graph of \(h\left( x \right) = {\left( {\frac{1}{2}} \right)^x}\) after the following transformation:

  • Stretch the graph by a factor of 2.
  • Then, shift the graph 3 units downward.
02

Sketch the graph of transformation from \(h\left( x \right) = {\left( {\frac{{\bf{1}}}{{\bf{2}}}} \right)^x}\), \(h\left( x \right) = {\bf{2}}{\left( {\frac{{\bf{1}}}{{\bf{2}}}} \right)^x}\) and \(h\left( x \right) = {\bf{2}}{\left( {\frac{{\bf{1}}}{{\bf{2}}}} \right)^x} - {\bf{3}}\)

The figure below represents the graph of \(h\left( x \right) = {\left( {\frac{1}{2}} \right)^x}\):

The figure below represents the graph of \(h\left( x \right) = 2{\left( {\frac{1}{2}} \right)^x}\):

The figure below represents the graph of \(h\left( x \right) = 2{\left( {\frac{1}{2}} \right)^x} - 2\):

Thus, the graph of the function is obtained.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.

Sign-up for free